PLEASE SIMPLIFY THE EXPRESSION!!!!!

Mathematics

2 answers:

slega [8]3 years ago

5 0

(2x24)+(2x42)

I am not sure

mafiozo [28]3 years ago

3 0

2+4 is 6 - 2, because 4-2 is 2 and then you multiply 3x6 and then subtract 2 from that

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Which dot plot matches the tally chart below?

Alla [95]

Can u post pictures of the tally chart

6 0

3 years ago

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The graph shows the result of a matrix transformation, where the pre-image has dashed lines Which matrix operation is represente

diamong [38]

The matrix operation is the addition subtraction and multiplication involving matrices. The coordinates of the image can be represented as a matrix obtained from the coordinates of the preimage through matrix operations

The best correct option is option D), (the y-coordinate for the point (8, -7) is to be replaced with a 7 to give (7, -7) as follows:

$\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]$

The reason the above matrix value for the matrix operation are correct are as follows:

Known parameters:

From the diagram, we have that the coordinates of the vertices of the preimage are;

(2, -5), (3, -7), (9, -3), and (7, -7)

The coordinates of the vertices of the image are;

(2, 5), (3, 7), (9, 3), and (7, 7)

Required:

The matrix operation for the transformation of the preimage points to the image points

Solution:

The transformation from the coordinates of the vertices of primage to the vertices of image involves the change in the sign from negative to positive, of the y-values of the image, which can be obtained by multiplying by (-1)

Therefore, the required matrix operation is presented as follows:

$\mathbf{\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]} =\left[\begin{array}{rrrr}9&7&3&2\\3&7&7&5\end{array}\right]$

Therefore, the best correct option is option D)

Learn more about matrix operations here:

brainly.com/question/17141646

3 0

3 years ago

Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with μ=10

Tju [1.3M]

Answer: 0.8238

Step-by-step explanation:

Given : Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with $\mu=106$ and $\sigma=15$ .

Let x denotes the scores on a certain intelligence test for children between ages 13 and 15 years.

Then, the proportion of children aged 13 to 15 years old have scores on this test above 92 will be :-

$P(x>92)=1-P(x\leq92)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{92-106}{15})\\\\=1-P(z\leq })\\\\=1-P(z\leq-0.93)=1-(1-P(z\leq0.93))\ \ [\because\ P(Z\leq -z)=1-P(Z\leq z)]\\\\=P(z\leq0.93)=0.8238\ \ [\text{By using z-value table.}]$