Answer:
5x + 6y = 20_____(1)
8x - 6y = -46_____(2)
Solving simultaneously:
Eqn(1) + Eqn(2)
5x + 8x + 6y + (-6y) = 20 + (-46)
13x = -26
x = -2
substituting this into Eqn (1):
5(-2) + 6y = 20
-10 + 6y = 20
6y = 30
y = 5
hence:
x = -2,y = 5.
Quadratic polynomial x^2 - x - 6 = f(x)
binomial (x-3)
dividing:-
x + 2
----------------------
x - 3 ) x^2 - x - 6
x^2 - 3x
----------
2x - 6
2x - 6
--------
.........
result of division is (x + 2)
s o we can write the function as (x - 3)(x + 2)
Part 2 f(a) = f(3) = (3)^2 - 3 - 6 = 0
Part3 The remainder Theorem states that the remainder when a polynomial is divided by (x - a) then the remainder is f(a). If f(a) = 0 then x - a is a factor.
In the above case f(3) = 0 therefore (x - 3) is a factor of our polynomial.
Answer:
Step-by-step explanation:
<u>Given</u>
- Q(s) = -4s^3 + 7s^2 - 24;
- s = -4 and 1
<u>Verifying zeroes</u>
Q(-4) =
- -4(-4)^3 + 7(-4)^2 - 24 =
- 256 + 112 - 24 =
- 344
- Incorrect as 344 ≠ 0
Q(1) =
- -4(1)^3 + 7(1)^2 - 24 =
- -12 + 7 - 24 =
- -29
- Incorrect as -29 ≠ 0
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