Answer:
D) In case 1, both PS I and PS II completely lose function; in case 2, a proton gradient is still produced.
Explanation:
The light dependent reaction of photosynthesis, which produces the ATP and NADPH needed in the light independent stage of the process, includes complexes of proteins and pigments called PHOTOSYSTEMS. These photosystems (I and II) are key to the functionality of the light dependent reactions in the thylakoid.
The major pigment present in both photosystems is CHLOROPHYLL A, which absorbs light energy and transfers electrons to the reaction center. Chlorophyll B is only an accessory pigment meaning it can be done without. Hence, if all of the chlorophyll A is inactivated in the algae but leaves chlorophyll B intact as in case 1, both PS I and PS II will lose their function because Chlorophyll A is the major pigment that absorbs light energy in both photosystems.
In case 2, if PS I is inhibited and PS II is unaffected, a PROTON GRADIENT WILL STILL BE PRODUCED because the splitting of water into protons (H+) and electrons (e-) occurs in PSII. Hence, H+ ions can still be pumped into the inner membrane of the thylakoid in order to build a proton gradient even without the occurrence of PS I.
Answer:
aceptable value is directly accessed where as experimental value is not coinfermed.
Answer:
I think it's d but I am not too sure
Answer:
The correct answer is - it obtains electrons from the oxygen atom in a water molecule, so it must have a stronger attraction for electrons than oxygen has
Explanation:
P680 known as which contains a reaction center in photosystem two, it is a very strong oxidizing agent that catalyzes the transfer of electrons from H2O to a bound quinone, with the production of O2.
To have a stronger attraction for electrons than oxygen has, P680 gets electrons from the O2 atom in a water molecule.
