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olganol [36]
3 years ago
14

What is pythagoras theorem​

Mathematics
1 answer:
Alborosie3 years ago
6 0

Answer:

hypotenuse²=base²x height²

Step-by-step explanation:

It is used to find the third side of a triangle.

Hope it helps :)

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The closest number to √42 is the option C, 6.5

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What is 1/2 times 1/2 times 2 times 12
4vir4ik [10]

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6

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3 years ago
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Find the area of the shaded portion in the square. Show all work for full credit.
kumpel [21]
Well, what I would do [not sure if it's the correct way], is use the white area as a sector of a circle. The top right of the box is the center of the circle, so the radius is 6.
Then, by the white portion being one quarter of the circle (90° out of 360°), I could calculate the that pink shaded region = the total square (6×6) minus the white sector.
So area (A) of white sector (s): A(s) = 1/4×pi×r^2
A(s) =  \frac{\pi {r}^{2} }{4}  =  \frac{\pi  \times {6}^{2} }{4}  \\ A(s) =  \frac{36\pi}{4}  = \frac{9\pi}{1}  = 9x3.142 \\ A(s) = 28.27
36 - 28.27 = 7.73
6 0
3 years ago
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Solve the equation 3^(2x) -4*3^(x+1) + 27 = 0. use rules of exponents to change 3^(x+1)​
Leviafan [203]

Answer:

\huge\boxed{x=1\ \vee\ x=2}

Step-by-step explanation:

3^{2x}-4\cdot3^{x+1}+27=0\\\\\text{use}\ (a^n)^m=a^{nm}\ \text{and}\ a^n\cdot a^m=a^{n+m}\\\\\left(3^x\right)^2-4\cdot3^x\cdot3^1+27=0\\\\\left(3^x\right)^2-12\cdot3^x+27=0\\\\\text{substitute}\ 3^x=t>0\\\\t^2-12t+27=0\\\\t^2-3t-9t+27=0\\\\t(t-3)-9(t-3)=0\\\\(t-3)(t-9)+0\iff t-3=0\ \vee\ t-9=0\\\\t-3=0\qquad\text{add 3 to both sides}\\\boxed{t=3}\\\\t-9=0\qquad\text{add 9 to both sides}\\\boxed{t=9}

\text{We return to substitution:}\\\\3^x=t\\\\3^x=3\ \vee\ 3^x=9\\\\3^x=3^1\ \vee\ 3^x=3^2\\\\\boxed{x=1}\ \vee\ \boxed{x=2}

4 0
3 years ago
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