I´d say "d" is the distance from the eye to the wall.
Now substracting 1.2-1 you´ll get the distance of the wall of the smallest triangle = 0.2 And you do 1.5-0.2= 0.3 that´s the distance of the wall of the other triangle. Then you solve everything with Pitagoras theorem. You have 2 rectangle triangles.
B+alfa=45°
tan^-1(0.2/d)=B
tan^-1(1.3/d)=alfa
THEN:
tan^-1(0.2/d)+tan^-1(1.3/d)=45°
Now you have 3 ecs and 3 variables.
alfa,B and "d"
There are 6 pockets all together. You checked two of them and it wasn't
there. So you can forget about those 2, and now there are 4 pockets left.
The total number of ways for your next try is 4.
The number that will be successful is 1.
The probability of success on the next one is <em>1/4 = 25% .</em>
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Another method of solution, somewhat more complex:
Total number of pockets = 6.
Amount of money missing = $10
First partial sum, i.e. sum of numbers
in the first part of the problem = 6 + 10 = 16.
Total number of pockets = 6
Current value of cargo pants on a fashion scale from 1 to 10 = -2.
Second partial sum = 6 - 2 = 4.
Probability = (second partial sum) / (first partial sum) = 4/16 = <em>25% </em>.
Let <em>f(x)</em> be the sum of the geometric series,
for |<em>x</em>| < 1. Then taking the derivative gives the desired sum,
Step-by-step explanation:
or
Hope it will help :)
Answer:
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Step-by-step explanation:
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