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2 years ago

5

How much material was required for each of two dresses of the same size if it took 5 1/2 yards for both

2 answers:

omeli [17]2 years ago

7 0

Answer: 11 yards of material was required for each of two dress of the same size.

Step-by-step explanation:

konstantin123 [22]2 years ago

5 0

Since both took 5 1/2 yards then you would have to add 5 1/2 yards together to get 11 yards

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2 years ago

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sergejj [24]

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2 years ago

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Sidana [21]

Answer:

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5 0

2 years ago

Read 2 more answers

In 2013, the moose population in a park was measured to be 5,100. By 2018, the population was measured again to be 5,200. If the

natka813 [3]

Answer:

$P(t) = 5100e^{0.0039t}$

Step-by-step explanation:

The exponential model for the population in t years after 2013 is given by:

$P(t) = P(0)e^{rt}$

In which P(0) is the population in 2013 and r is the growth rate.

In 2013, the moose population in a park was measured to be 5,100

This means that $P(0) = 5100$

So

$P(t) = 5100e^{rt}$

By 2018, the population was measured again to be 5,200.

2018 is 2018-2013 = 5 years after 2013.

So this means that $P(5) = 5200$ .

We use this to find r.

$P(t) = 5100e^{rt}$

$5200 = 5100e^{5r}$

$e^{5r} = \frac{52}{51}$

$\ln{e^{5r}} = \ln{\frac{52}{51}}$

$5r = \ln{\frac{52}{51}}$

$r = \frac{\ln{\frac{52}{51}}}{5}$

$r = 0.0039$

So the equation for the moose population is:

$P(t) = 5100e^{0.0039t}$

5 0

2 years ago

Quick algebra 1 question for 10 points!

zaharov [31]

<u>Answer:</u>

○ $x = -7$

<u>Step-by-step explanation:</u>

Given the equation:

$10(x + 10) - 4 = 11 - 5(2x + 11)$ ,

to solve for $x$ , we have to rearrange the equation to make $x$ its subject.

$10(x + 10) - 4 = 11 - 5(2x + 11)$

⇒ $10x + 100 - 4 = 11 - 10x -55$ [expand brackets]

⇒ $10x + 96 = -44 - 10x$

⇒ $10x + 10x + 96 = -44$ [add $10x$ to both sides]

⇒ $20x + 96 = -44$

⇒ $20x = -44 - 96$ [subtract 96 from both sides]

⇒ $20x = -140$

⇒ $x = \frac{-140}{20}$ [divide both sides by 20]

⇒ $x = \bf-7$

6 0

1 year ago

Read 2 more answers