A quarter, two dimes, and two pennies.
That would be :
4x – 10 = x2 – 5x + 10 ( y = 4x - 10 is substitute for y)
PROOF: y + 5x = x²<span> + 10
</span> (4x - 10) + 5x = x² + 10
4x - 10 = x² -5x + 10
<span>
</span>0 = x2 – 9x + 20<span> (liked terms are grouped and simplified)
PROOF: </span> 4x - 10 = x² -5x + 10
4x = x² -5x + 10 + 10
0 = x² -5x -4x + 20
0 = x² - 9x + 20
Solving:
x² - 9x + 20 = 0
x² - 5x - 4x + 20 = 0
(x - 5) (x - 4) = 0
⇒ x = 4 (as question says) OR x = 5
Answer:lol
Step-by-step explanation:
hahaha
Answer:
-9x^3+4x^2+5
Step-by-step explanation:
(6x^2 - 3 - 5x^3) - (4x^3 +2x^2 - 8)
distribute the minus sign
(6x^2 - 3 - 5x^3) - 4x^3 -2x^2 + 8
Combine like terms
-5x^3 -4x^3 +6x^2 - 2x^2 -3 +8
-9x^3+4x^2+5
So there is 15 different outcomes which we want 6 of them 2, 3, 5, 7, 11 all prime numbers so a 6/15 chance we’d pull a prime number
6/15 or 40% chance we’d pull a prime number out of the bag
