The maximum height and horizontal distance is required.
Maximum height 8 feet; horizontal distance 16 feet
The given path is 
If the skateboarder jumps at x = 0 she will land at y = 0. However there will be at horizontal displacement.
or
The distance between -5 and 11 is 
Middle point would be 
from 
.
So, 
The maximum height will be
The maximum height is 8 feet and the horizontal distance is 16 feet.
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Answer:
135 In the 3rd year
Step-by-step explanation:
240-35= 205
205-35=170
170-35=135 (Or just use a calculator)
The answer would be 120 hope this helps!!
If it is being pulled in at a constant rate of 3ft/sec, then it is travelling 3 ft/sec is it not? knot? lol
Answer:
=(1) 2x*2x*2x = 8x^3
(2) -3y^2* -3y^2* -3y^2 = 
(3) 2x * -3y^2 * 2x = -12 x^2 y^2
(4)-3y^2*-3y^2*2x = 18xy^4
(5) -3y^2*-3y^2*2x = 18xy^4
(6) 3y^2*-3y^2*2x = 18xy^4
(7) 2x * -3y^2 * 2x = -12 x^2 y^2
(8)2x * -3y^2 * 2x = -12 x^2 y^2
final answer: 
