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2 years ago

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A child who is 4 ½ feet tall casts a 6-foot shadow. At the same time, a nearby statue casts a 15-foot shadow. How tall is the st

atue?

1 answer:

stiv31 [10]2 years ago

5 0

Answer:

13 1/2 tall

Step-by-step explanation:

If 4 1/2 is the childs hight and their shadow is 6 feet, the shadow adds 2 1/2 to the height.

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The weight of a bull clad is 388 kilograms. If it’s weight increases at a rate of 1 2/5 kilograms per day how long it will take

Alex73 [517]

Answer:

It will take <u><em>80 days</em></u> for the bull calf to reach a weight of 500 kilograms.

Step-by-step explanation:

Given:

The weight of a bull calf is 388 kilograms.

Now, to find the weight of bull calf of how long it will take to reach a weight of 500 kilograms, if it’s weight increases at a rate of 1 2/5 kilograms per day.

Required weight which to be increased = 500 - 388 = 112 kilograms.

Rate of weight increase = $1\frac{2}{5}=\frac{7}{5}$

= $1.4\ kilograms.$

Thus, the time required = $\frac{required\ weight}{rate\ of\ weight}$

= $\frac{112}{1.4}$

= $80.$

<em>The time required = 80 days</em>.

Therefore, it will take 80 days for the bull calf to reach a weight of 500 kilograms.

5 0

3 years ago

Peter uses the equation y = StartFraction 13 over 4 EndFraction x to model the number of miles that he has walked in x hours. Wh

Umnica [9.8K]

The true statement is Peter walks at a rate of 13 over 4 miles per hour.

<h3>What is the true statement?
</h3>

Direct variation is when two variables move in the same direction. If one variable increases, the other variable increases. When the hour Peter walks increases, the distance he walks also increases.

Here are the options:

Peter walks at a rate of StartFraction 4 over 13 EndFraction miles per hour.

Peter walks at a rate of 4 miles per hour.

Peter walks at a rate of StartFraction 13 over 4 EndFraction miles per hour.

Peter walks at a rate of 13 miles per hour.

To learn more about direct variation, please check: brainly.com/question/27573249

#SPJ1

8 0

2 years ago

PLS HELP ME FAST WILL GIVE POINTS

SpyIntel [72]

Answer:

The scale factor of the dilation that transforms the triangle is 1/3

Step-by-step explanation:

9x1/3 is 3. 6x1/3 is 2, etc.

5 0

2 years ago

1. What is the value of the y variable in the solution to the following system of equations?

ollegr [7]

Part 1)

we have

$3x-6y=3$ ------> equation A

$7x-5y=-11$ ------> equation B

Multiply by $-7$ the equation A

$-7(3x-6y)=-7*3$

$-21x+42y=-21$ ------> equation C

Multiply by $3$ the equation B

$3*(7x-5y)=-11*3$

$21x-15y=-33$ -------> equation D

Adds equation C and equation D

$-21x+42y=-21 \\21x-15y=-33\\---------- \\ 42y-15y=-21-33\\27y=-54 \\ y=-2$

therefore

<u>the answer Part 1) is the option A </u>

$y=-2$

Part 2)

we have

$3x+y=6$

$y=-3x+6$ ------> equation A

$6x+2y=8$

Simplify Divide by $2$ both sides

$3x+y=4$

$y=-3x+4$ ------> equation B

the lines A and B are parallel lines, because the slope m is equal

so

The system has no solution

therefore

<u>the answer Part 2) is the option D</u>

There is no x value as there is no solution to the system.

Part 3)

we have

$4x+2y=6$ ------> equation A

$x-y=3$

$y=x-3$ ------> equation B

substitute equation B in equation A

$4x+2[x-3]=6$

$6x-6=6$

$6x=12$

$x=2$

therefore

<u>the answer part 3) is the option D</u>

$x=2$

Part 4)

Let

x---------> The number of one-step equations

y---------> The number of two-step equations

we know that

$x+y=1,120$

$x=1,120-y$ -------> equation A

$3x-2y=1,300$ ------> equation B

substitute equation A in equation B

$3[1,120-y]-2y=1,300$

$3,360-5y=1,300$

$5y=3,360-1,300$

$5y=2,060$

$y=412$

therefore

<u>the answer part 4) is the option D</u>

$y=412$

8 0

3 years ago

Read 2 more answers

a mountaineer climbed 1,000 feet at a rate of x feet per hour, he climbed and additional 5,000 feet at a different rate. this ra

marshall27 [118]

A mountaineer climbed 1000 feet at a rate of x feet/hour

1000 = x ( t 1 ) eq1

5000 = X ( t 2) eq2 ( he climbed additional at different rate )

the rate was 10 feet / hour less than twice the first rate

X = 2x - 10 eq3

take eq1 and eq 2

( total time = t 1 + t 2 = T)

T = 1000/x + 5000/X

but X = 2x-10

T = 1000/x + 5000/( 2x -10)

T = 1000/x + 5000/( 2(x-5))

T = 1000/x + 2500 / (x-5)

3 0

3 years ago

Read 2 more answers