Answer:
Option (1)
Step-by-step explanation:
From the picture attached,
Triangle CAB is a right triangle.
Therefore, m∠1 = 90°
Similarly, m∠ACD = 90°
m∠ACD = m∠ACB + m∠BCD = 90°
= m∠3 + m∠4 = 90°
Since m∠4 = 35°,
m∠3 + 35° = 90°
m∠3 = 90° - 35°
= 55°
In the triangle ABC,
m∠ACB + m∠CBA + m∠BAC = 180° [Property of a triangle]
m∠3 + m∠2 + m∠1 = 180°
55° + m∠2 + 90° = 180°
m∠2 + 145° = 180°
m∠2 = 180° - 145°
= 35°
Since, AB║CD and BC is a transverse,
Therefore, m∠2 = m∠4 = 35° [Alternate interior angles]
Option (1) is the correct option.
Y = -5x + 28
will be parallel to your equation because it has the same coefficient but will also pass through (3, 13)
hello ....
the equation of a plane that is ; ax+by+cz +d =0
the vector perpendicular to this plane is : V(a,b,c)
in this exercice ; a = -4 b= -4 c = -1
then: the equation of a plane that is ; -4x-4y-z +d =0
but the plane passing through the point (−2,−5,5) :
-4(-2)-4(-5)-(5) +d =0
23+d =0
d =-23
the equation of a plane is : -4x-4y-z-23 =0
11 hours because you cross multiply and then divide by 60 since time
Answer:
d. 3 to the power of 2 multiplied by 1 whole over 4, the whole squared. = 3 to the power of 4 multiplied by 1 squared over 4 squared. = 81 over 16.
Step-by-step explanation:
This is an exercise in PEMDAS, the order of arithmetic operation:
parentheses > exponents > multiplication and division > addition and subtraction.
[(3² × 5⁰)/4]² = [(9 × 1)/4]² = (9/4)² = 81/16
3⁴ × 1²/4² = 81 × 1/16 = 81/16
a. is wrong. 3¹ × 1²/4² = 3 × 1/16 = 3/16
b. is wrong. [(3² × 0)/4]² = [(9 × 0)/4]² = (0/4)² = 0² = 0
c. is wrong. [(3² × 0)/4]² = 0
