Equilateral triangle with the side 4 cm and h=2.5 cm
In equilateral triangle all sides are equal
so all sides are equal in the base of the prism
lateral area of the prism = Perimeter of the base * height
Perimeter of the base equilateral triangle = side + side + side
lateral area of the prism =(side + side + side) * height
= (4+4+4) * 2.5
= 
lateral area of the prism =
Answer:
"g(x) = log₂(x) + 2" is the closest graph to what g(x) would be, slightly above f(x) and curving up.
Answer:
the like terms were not grouped together.
Look at the face of the pyramid facing you. The length of the base of this pyramid is 82 m; half of that is 41 m.
If you were to draw a straight vertical line through the vertex of the pyramid, the bottom of this line would be at the very center of the base and also be 41 in perpendicular distance from any of the edges of the base of this pyramid.
Let the height of the pyramid be y, as measured upward from the center of the base of the pyramid. This center is, as before, 41 m from any side of the pyramid base, a horiz. distance.
Then, tan 52 deg = y / 41 m, and so y = height of pyramid =
(41 m)(tan 52 deg) = (41 m) (1.28) = 52.48 m
