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sleet_krkn [62]
3 years ago
7

A researcher interested in vocabulary development obtains a sample of twenty 3-year old children to participate in a research st

udy. The average (i.e., mean) score for the group of 20 is an example of a(n)___________.
a) sample
b) statistic
c) population
d) parameter
Mathematics
1 answer:
Andreyy893 years ago
4 0

Answer: b) statistic

Step-by-step explanation:

  • Population = A large groups of individuals sharing the same or similar characteristic by the point og study.
  • Sample  = It is a subset of population .
  • Parameter = It is measure of characteristic in population.
  • Statistic =  It is measure of characteristic in sample.

Since the average score was taken by the group of 20 which is nothing but the sample.

That means, the average score is an example of<u> statistic</u>.

Hence, the correct option is b) statistic .

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B. You can make 50 servings of punch. 20 servings divided by 8 ounces is 2.5 ounces. 2.5 ounces times 20 ounces equals 50 servings.
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√32/6<br> Please show all work when answering!!
BARSIC [14]


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Alternative form:

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F(x)=(3+x)/(x-3), what is f(a+2)
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\bf f(x) = \cfrac{3+x}{x-3} ~\hfill f(a+2)=\cfrac{3+(a+2)}{(a+2)-3}\implies f(a+2)=\cfrac{a+5}{a-1}

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Answer for all please
malfutka [58]

Answer:

a) 'X' be the random variable in discrete distribution

b) <em> The value of y = 0.2</em>

<em>c) The mean value or  Expectation value</em>

<em>E (X) = 1.25</em>

<em>d) </em>

<em>The variance σ² of the discrete distribution function is</em>

<em>Variance ( V(x)= 1.2875</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given data

 x    :      0              1        2        3        4

P(x)  :     0.30      0.35      y      0.10   0.05

a)

  Let 'X' be the random variable in discrete distribution

 Given data is discrete distribution

<em>i) If the numbers </em>p(x_{i} )\geq 0  for all values of 'i'

ii) ∑P(x) = 1

Given data <em> </em>p(x_{i} )\geq 0  for all values of 'i'

∑P(x) = 1

0.30+0.35+y+0.10+0.05 =1

                  y + 0.8 = 1

                 y = 1 -0.8 = 0.2

<em>b) The value of y = 0.2</em>

<u><em>Step(ii):-</em></u>

<u><em>Expectation:</em></u>

Given data

 x    :      0              1          2        3        4

P(x)  :     0.30      0.35      0.2      0.10   0.05

<em>The mean value or  Expectation value</em>

<em>E (x) = ∑ x p ( X = x)</em>

<em>         =  0 × 0.30 + 1 × 0.35 + 2 × 0.2 + 3 × 0.10 + 4 × 0.05</em>

<em>        =     0 + 0.35 + 0.4 + 0.30 + 0.2</em>

<em>       =       1.25</em>

<u><em>Variance of X</em></u>

The variance σ² of the discrete distribution function is defined by

                σ²  = ∑ x² p(x=x) - μ²

                     = 0× 0.30 + 1² × 0.35 + 2²× 0.2 +3²× 0.10 + 4²× 0.05 - (1.25)²

                    = 0 + 0.35 + 0.8 + 0.9 + 0.8 - 1.5625

                   = 1.2875

<u><em>conclusion:-</em></u>

<em>The mean value or  Expectation value = 1.25</em>

<em>The variance σ² of the discrete distribution function</em>

<em>  V(X) = 1.2875</em>

   

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