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4 years ago

9. At the football club there are 3 boys for every 2 girls. There are

Mathematics

2 answers:

Wittaler [7]4 years ago

7 0

Answer:

Step-by-step explanation:

77julia77 [94]4 years ago

4 0

Answer:

hay 20 chicas

Step-by-step explanation:

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0.5,1/5,0.35,12/35,4/5 least to greatest

PSYCHO15rus [73]

The order is:
1/5, 12/25, 0.35, 0.5, 4/5.

5 0

4 years ago

Read 2 more answers

Shipping rates for Company A and Company B are shown in the tables below. Which company has shipping rates that you can represen

meriva

Company B; the ratios of cost to weight are equivalent.

Step-by-step explanation:

Step 1:

In the equation, $y=kx$ k is the constant of proportionality.

If the values are in accordance with $y=kx$ , the values of k will be constant for all the values.

So we determine the values of k for both the companies and see which has a constant k.

If $y=kx, k = \frac{y}{x}$ . In these tables, y is the total cost and x is the weight in lbs.

Step 2:

For company A,

when $y=10.55, x=1, k = \frac{10.55}{1} = 10.55,$

when $y=10.85, x=2, k = \frac{10.85}{2} = 5.425,$

when $y=11.15, x=3, k = \frac{11.15}{3} = 3.71666.$

For company B,

when $y=2.75, x=1, k = \frac2.75}{1} = 2.75,$

when $y=5.50, x=2, k = \frac{5.50}{2} = 2.75,$

when $y=8.25, x=3, k = \frac{8.25}{3} = 2.75.$

So company B has a constant value of $k=2.75$ .

3 0

3 years ago

3x - 2x^2 + 7 - 3x^2

inn [45]

3x-2x^2+7-3x^2
=3x-2x^2-3x^2+7
=3x-5x^2+7
=-5x^2+3x+7 that’s how it’s solved and that’s the answer as well. Come back for help

7 0

3 years ago

What is the scale on a map or drawing used for

ivanzaharov [21]

Answer:

cm scale

Step-by-step explanation:

it may help you to understand

3 0

3 years ago

Which of the following is not one of the 8th roots of unity?

Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1. Since $z=1=1+0\cdot i,$ then

$Rez=1,\\ \\Im z=0$

and

$|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.$

This gives you $\varphi=0.$

Thus,

$z=1\cdot(\cos 0+i\sin 0).$

2. The 8th roots can be calculated using following formula:

$\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.$

Now

at k=0, $z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;$

at k=1, $z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=2, $z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;$

at k=3, $z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=4, $z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;$

at k=5, $z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

at k=6, $z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;$

at k=7, $z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

The 8th roots are

$\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.$

Option C is icncorrect.

5 0

3 years ago