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3 years ago

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9. Khalid drove 66 miles on 3 gallons of gasoline. Which is the number of miles he could drive on 12 gallons of gasoline?

1 answer:

IrinaK [193]3 years ago

8 0

Answer:

264 miles

Step-by-step explanation:

Find the unit rate (mpg):

66 miles

----------------- = 22 mpg

3 gallons

On 12 gallons he could drive (22 mpg)(12 gallons) = 264 miles

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Find the length of side a.<br> 10<br> A<br> 6<br> A. 4<br> B. 64<br> C. V 136<br> D. 8<br> PREVIOUS

dedylja [7]

Answer:

D .8

Step-by-step explanation:

hypotenuse (h) = 10

base (b) = 6

perpendicular (p) = a= ?

We know by using Pythagoras theorem we get

p = √ h² - b²

a = √ 10² - 6²

a = √ 64

a = 8

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2 years ago

Find the surface area of a square pyramid with a length of 5 cm and a slant height of 8cm.

Tems11 [23]

Area of the square base = 5^2 = 25 cm^2
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= (1/3) pi * 5^2 * 8
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3 years ago

What is 12 and 19 /20 as a decimal?

-BARSIC- [3]

12.95

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3 years ago

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How should you write the proportion 9:36 = 10:40 using words?

JulijaS [17]

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3 years ago

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The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

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3 years ago