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3 years ago

14

3 1/5 divided by 1/3

1 answer:

nikdorinn [45]3 years ago

3 0

Answer:

9.6 OR 48/5 OR 9 3/5

Step-by-step explanation:

Reduce the expression, if possible, by canceling the common factors.

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What is the solution for y=4x−9

nignag [31]

To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.

x-intercept: (9/4,0)

y-intercept: (0,−9)

7 0

4 years ago

What is the slope of the line equation 7x-3y=21

kramer

Equation: 7x - 3y = 21

3y = 7x - 21

Divide both sides by 3,

y = 7/3x - 7

Compare it with principle equation, y = mx + c

Here, slope (m) = 7/3

In short, Your Answer would be: 7/3

Hope this helps!

8 0

3 years ago

Help with 21 please 22 is not needed

Gwar [14]

We can't see the whole question :/

8 0

3 years ago

The mean value of land and buildings per acre from a sample of farms is $1300, with a standard deviation of $200. The data se

Whitepunk [10]

Answer:

number of farms are 108

Step-by-step explanation:

4 0

3 years ago

Each day, Robin commutes to work by bike with probability 0.4 and by walking with probability 0.6. When biking to work injuries

kvasek [131]

Answer:

64.65% probability of at least one injury commuting to work in the next 20 years

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Each day:

Bikes to work with probability 0.4.

If he bikes to work, 0.1 injuries per year.

Walks to work with probability 0.6.

If he walks to work, 0.02 injuries per year.

20 years.

So

$\mu = 20*(0.4*0.1 + 0.6*0.02) = 1.04$

Either he suffers no injuries, or he suffer at least one injury. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-1.04}*1.04^{0}}{(0)!} = 0.3535
$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.3535 = 0.6465$

64.65% probability of at least one injury commuting to work in the next 20 years

3 0

3 years ago