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fredd [130]
2 years ago
10

Laura is training to run a race. She keeps track of the number of miles she runs. She has been training for 5 weeks, and she has

run a total
of 40 miles. At what rate has she been running, in miles per week?
Mathematics
1 answer:
V125BC [204]2 years ago
4 0

Answer:

8 miles per week!

Step-by-step explanation:

40 miles / 5 weeks = 8!

so it would be 8 miles per week.

i hope this helps!!

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Determine the GCF of 56f^3 g^2 and 70fg^3
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D. 14f^3 g^3  

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Solve f - 6 = 3f + 1
LUCKY_DIMON [66]
Simplifying f + -6 = 3f + 1 Reorder the terms: -6 + f = 3f + 1 Reorder the terms: -6 + f = 1 + 3f Solving -6 + f = 1 + 3f Solving for variable 'f'. Move all terms containing f to the left, all other terms to the right. Add '-3f' to each side of the equation. -6 + f + -3f = 1 + 3f + -3f Combine like terms: f + -3f = -2f -6 + -2f = 1 + 3f + -3f Combine like terms: 3f + -3f = 0 -6 + -2f = 1 + 0 -6 + -2f = 1 Add '6' to each side of the equation. -6 + 6 + -2f = 1 + 6 Combine like terms: -6 + 6 = 0 0 + -2f = 1 + 6 -2f = 1 + 6 Combine like terms: 1 + 6 = 7 -2f = 7 Divide each side by '-2'. f = -3.5 Simplifying f = -3.5

7 0
4 years ago
Read 2 more answers
Write prime factorizations of the number 18.
Nat2105 [25]

Answer:

18 is a composite number. 18 = 1 x 18, 2 x 9, or 3 x 6. Factors of 18: 1, 2, 3, 6, 9, 18.

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4 0
3 years ago
Please help me to solve the question. (chapter angle between two lines)​
dsp73

Answer:    \bold{x^2-\dfrac{181}{13}xy+12y^2=0}

<u>Step-by-step explanation:</u>

\tan \theta =\dfrac{y}{x}\quad \longrightarrow \theta=\tan ^{-1}\bigg(\dfrac{y}{x}\bigg)

\text{Given:}\quad \theta =\tan^{-1}\bigg(\dfrac{1}{13}\bigg)\quad \longrightarrow x=13,y=1

Insert x = 13 and y = 1:

x² + 2hxy + 12y² = 0

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169 + 26h + 12 = 0

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\text{Insert:}\ h=-\dfrac{181}{26}

x^2 + 2\bigg(-\dfrac{181}{26}\bigg) xy + 12y^2 = 0

\bold{x^2 -\bigg(\dfrac{181}{13}\bigg) xy + 12y^2 = 0}

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3 years ago
Which expression is equivalent to −1.3+(−4.9)+(−2.6) ?
Nesterboy [21]

Answer:

Step-by-step explanation:

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Is the answer!ihope this helps you :)

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