2 years ago

Quadrilateral ABCD is a rhombus. AD = 13 cm & BD = 24 cm, find AC

Mathematics

1 answer:

iogann1982 [59]2 years ago

8 0

Answer:

Step-by-step explanation:

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Find the acute angle between the two given lines<br><br> y=-2x and y=x

Marina CMI [18]

Answer:

θ ≈ 71.6°

Step-by-step explanation:

The angle between two lines with slopes m₁ and m₂ is:

tan θ = | (m₂ − m₁) / (1 + m₁m₂) |

Here, m₁ = -2 and m₂ = 1.

tan θ = | (1 − (-2)) / (1 + (-2)(1)) |

tan θ = | 3 / -1 |

tan θ = 3

θ ≈ 71.6°

3 0

3 years ago

If I decline by 23%, what percent would be remaining?

egoroff_w [7]

Answer: 77%

Step-by-step explanation:

100-23=77

Hope it helps!

4 0

2 years ago

6 + −28 − x = -2<br> -------------<br> x

nexus9112 [7]

The answer is x=-20.
6+ -28 -x =-2
You first add 28 to each side=6+-x=26 then you minus 6 from each side=-x=20.
Then you divide 20 by -x resulting in x=-20

3 0

3 years ago

Read 2 more answers

Assuming the pattern continues, what are the next two terms in this

pshichka [43]

D. 53, 107
The pattern is multiplying the previous number by two and then adding one to it.

4 0

3 years ago

PROBLEM 2 The height of a golf ball in feet can be determined using the formula h(t) = -16t2 + 100x , where t is the number of s

wolverine [178]

Answer:

Step-by-step explanation:

Given the height of a golf ball in feet modelled by the formula h(t) = -16t² + 100x where t is in seconds, we are to find the height of the golf after 2.5 seconds. To do that we will simply substitute t = 2.5secs into the formula given;

$h(t) = -16t^2 + 100x\\\\h(2.5) = -16(2.5)^2 + 100(2.5)\\\\h(2.5) = -16(6.25) + 250\\\\h(2.5) = -100+250\\\\h(2.5) = 150\\\\$

Hence the height of the golf after 2.5 seconds is 150ft.

8 0

3 years ago