Answer:2592/25
Step-by-step explanation: Big circle is pi*r^2= (4+3+3)^2*pi =314.15 minus 4^2*pi=50.26 equals 263.89. the big circle minus the first 2 layers of the circle = the outer circle. 314.15-(4+3)^2*pi=160.21 263.89-160.21=2592/25
Rewrite it without stem-and-leaf:
16,18,23,26,26,34,37,37,40,41,46
MEAN =∑(16,18,23,26,26,34,37,37,40,41,46)/11
MEAN =(16+18+23+25+26+34+37+37+40+41+46)/11 =343/11 = 31.18
MEDIAN (CENTRAL VALUE) = 34 (EQUIDISTANT FROM THE 2 EXTRENITIES)
MODE = THE HIGHEST FREQUENCY OF A NUMBER: only 34 appear twice, then the MODE is 34 that appears 2 times
if the diameter is 20, the its radius must be half that or 10.
![\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ A=5\pi \\ r=10 \end{cases}\implies \begin{array}{llll} 5\pi =\cfrac{\theta \pi (10)^2}{360}\implies 5\pi =\cfrac{5\pi \theta }{18} \\\\\\ \cfrac{5\pi }{5\pi }=\cfrac{\theta }{18}\implies 1=\cfrac{\theta }{18}\implies 18=\theta \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20sector%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%20r%5E2%7D%7B360%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20%5Ctheta%20%3D%5Cstackrel%7Bdegrees%7D%7Bangle%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20A%3D5%5Cpi%20%5C%5C%20r%3D10%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%205%5Cpi%20%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%20%2810%29%5E2%7D%7B360%7D%5Cimplies%205%5Cpi%20%3D%5Ccfrac%7B5%5Cpi%20%5Ctheta%20%7D%7B18%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B5%5Cpi%20%7D%7B5%5Cpi%20%7D%3D%5Ccfrac%7B%5Ctheta%20%7D%7B18%7D%5Cimplies%201%3D%5Ccfrac%7B%5Ctheta%20%7D%7B18%7D%5Cimplies%2018%3D%5Ctheta%20%5Cend%7Barray%7D)
Answer:2
Step-by-step explanation:
Answer:
a(-1)^(n-1).
Step-by-step explanation:
This is a Geometric Sequence with common ratio r = -1.
The general term is a(-1)^(n-1).