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Maru [420]
3 years ago
13

Which of the following is the general term for the sequence a, -a, a, -a, . . . ?

Mathematics
1 answer:
Nataly_w [17]2 years ago
5 0

Answer:

a(-1)^(n-1).

Step-by-step explanation:

This is a Geometric Sequence with common ratio r = -1.

The general term is a(-1)^(n-1).

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The scale factor of the dimensions of two similar wood floors is 4:3. It costs $207 to refinish the smaller wood floor. At that
Crank

Answer:

$276

Step-by-step explanation:

Create a proportion where x is the cost to refinish the larger wood floor:

\frac{4}{3} = \frac{x}{207}

Cross multiply and solve for x:

3x = 828

x = 276

So, to refinish the larger wood floor, it would cost $276

6 0
2 years ago
Order from least to greatest
RUDIKE [14]
Do them backwards and you will get the answer
5 0
3 years ago
Read 2 more answers
Can people help me on this please I need it!!! It’s really important
Firdavs [7]

Answer:

62

Step-by-step explanation:

The total of a triangle is 180

so 78+48 is 118

180-118=62

5 0
2 years ago
Can someone help me with this? Right answer gets brainliest!! :)
Sedbober [7]

I have 2 answers in mind

Answer #1:

\frac{y}{z}

Step-by-step explanation:

quotient means the answer to 2 things being divided so the quotient of y and z would be \frac{y}{z} because there is no numerical value.

Answer #2:

1

Step-by-step explanation:

Usually, when a letter is left by itself in an equation it usually has an invisible one in front of it. so when dividing y by z it would equal 1/1 which is equal to one.

Hope this helps :)

6 0
3 years ago
1
Kazeer [188]

Answer:

D

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 4, 29) and (x₂, y₂ ) = (0, 28) ← 2 ordered pairs from the table

m = \frac{28-29}{0+4} = - \frac{1}{4}

The line crosses the y- axis at (0, 28 ) ⇒ c = 28

y = - \frac{1}{4} x + 28 ← equation of line → D

8 0
3 years ago
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