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Oxana [17]
3 years ago
11

-3y^10-5y^14: Write in standard form, find the degree, and classify the number of terms

Mathematics
1 answer:
alisha [4.7K]3 years ago
7 0

Answer:

STANDARD: -5y^14 -3y^10

DEGREE: 14

NUMBER OF TERMS: 2

Step-by-step explanation:

Two terms, the highest degree is 14, and standard has the term with the highest degree in the front.

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What is the answer to 5m + 30 = 60
Keith_Richards [23]

Answer:

m = 6

Step-by-step explanation:

Given

5m + 30 = 60 ( subtract 30 from both sides )

5m = 30 ( divide both sides by 5 )

m = 6

6 0
3 years ago
A shopkeeper sold a dressing table for 7512.75 at a profit of 19*1/4% What was the cost price.​
Katarina [22]
Cp=7512.75×[100÷(100+77÷4)]
=7512.75×(100÷119.25)
=6300
c.p=6300
4 0
3 years ago
Yesterday noah ran 2 1/2 miles in 3/5 hour. Emily ran 3 3/4 miles in 5/6 hour. Anna ran 3 1/2 miles in 3/4 hour how fast in mile
Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

To calculate the speed of each one we proceed as follows:

speed=distance/time

a] Noah's speed:

distance=2.5 miles

time=3/5 hours

speed=(2 1/2)/(3/5)

=(5/2)/(3/5)

=5/2×5/3

=25/6

=4 1/6 mi/hr

Emily's speed

distance=3 3/4 miles

time=5/6 hour

thus

speed=(3 3/4)/(5/6)

=15/4)/(5/6)

=15/4×6/5

=4 1/2 mi/hr

Anna's speed:

distance=3 1/3 miles

time=3/5

speed=(3 1/3)/(3/5

=(10/3)/(3/5)

=10/3×5/3

=5 5/9 mi/hr

Anna was the fastest

6 0
2 years ago
Read 2 more answers
A researcher conducted a paired sample t-test to determine if advertisements were viewed more in the morning (before noon) or in
Natalija [7]

Answer:

b. No, there was no difference between Morning (M= 32), and Evening (M=40.625), (t [7] = 1.15, p > .05).

Step-by-step explanation:

The critical value for one tailed test is t ∝(7) > 1.895

A one tailed test is performed to test the claim that advertisements were viewed more in the morning (before noon) or in the evening (after 5pm)

The null and alternative hypotheses are

H0: μm = μe   vs     Ha μm > μe

where μm is the mean of the morning and μe is the mean of evening.

The calculated value of t = -1.152587077  which is less than the critical region hence the null hypothesis cannot be rejected .

P(T<=t) one-tail 0.143458126 > 0.05

If two tailed test is performed the critical region is t Critical two-tail 2.364624252

and the calculated t value is  -1.152587077  which again does not lie in the critical region .

Hence μm =  μe or    μm ≤ μe

P(T<=t) two-tail 0.286916252  > 0.025

Therefore

b. No, there was no difference between Morning (M= 32), and Evening (M=40.625), (t [7] = 1.15, p > .05).

Option b gives the best answer.

6 0
3 years ago
Help please I will give brainliest ❤​
Maslowich

Step-by-step explanation:

a < (a + b)/2 < b

Solve the first inequality.

a < (a + b)/2

2a < a + b

a < b

Solve the second inequality.

(a + b)/2 < b

a + b < 2b

a < b

Both inequalities are true.  Therefore, a < (a + b)/2 < b.

6 0
3 years ago
Read 2 more answers
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