Question

A particular circle in the standard (x,y) coordinate

Answer 1

$the\ center\ of\ the\ circle:(a;\ b)\\the\ radius:r\\\\then\ the\ circle:(x-a)^2+(y-b)^2=r^2\\\\=========================\\\\(x-5)^2+y^2=38\\\\(x-5)^2+(y-0)^2=(\sqrt{38})^2\\\\center:(5;\ 0)\\radius:\sqrt{38}$