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Shtirlitz [24]
3 years ago
7

Suppose that you live in a community that has 125,000 households. Among these households, 50,000 have traditional landline telep

hones while the remaining 75,000 only use cellular and / or VOIP telephones. We are going to select 100 households from your community at random without replacement. The first household selected does not have a traditional landline telephone. What is the probability that the second household selected will have a traditional landline telephone
Mathematics
1 answer:
DedPeter [7]3 years ago
6 0

Answer:

0.4 = 40% probability that the second household selected will have a traditional landline telephone

Step-by-step explanation:

A probability is given by the number of desired outcomes divided by the number of total outcomes.

We have that:

125,000 households

50,000 have traditional landlines telephones.

The first household selected does not have a traditional landline telephone.

Now we have 125000 - 1 = 124,999 households, and 50,000 have traditional landlines telephones.

What is the probability that the second household selected will have a traditional landline telephone

p = \frac{50000}{124999} = 0.4

0.4 = 40% probability that the second household selected will have a traditional landline telephone

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3 years ago
What is the outlier in the following data set:<br> 15,11,10,8,9,1,8,7,5,4,2,3, and 37?
NeTakaya

Step-by-step explanation:

The steps to find an outlier:

1. Put the data in numerical order.

2. Find the median.

3. Find the medians for the top and bottom parts of the data. This divides the data into 4 equal parts.

The median with the smallest value is called Q1. The median for all the values - usually just called the median is also called Q2. The median with the largest value is Q3.

4. Subtract...Q3 - Q1. This value is the InterQuartileRange or IQR. Remember that the range means taking the largest minus the smallest. This is a special range having to do with the quartiles.

5. Multiply...1.5 * IQR

6. Take your answer from #5 and do 2 things with it. A). Subtract it from Q1 and B) Additional to Q3.

7. Look at all your data points. If any are SMALLER than Q1 - 1.5 *IQR, they are outliers. If any are LARGER than Q3 + 1.5 *IQR, they are also outliers.

For your data....the median, Q2 is

(43+38)/2 = 40.5.

Q1 = (30+26)/2 = 28.

Q3 = (54+52)/2 = 53

The IQR is 53 - 28 = 25

1.5 * IQR = 37.5

Q1 - 37.5 = 28 - 37.5 = -9.5. There is no data value less than -9.5.

Q3 + 37.5 = 53 + 37.5 = 90.5. there is no data value greater than 90.5.

My conclusion is that there are no outliers in this data.

I hope this helps!

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3 years ago
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Answer:

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Step-by-step explanation:

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Thomas: $24.50 for 10km -> 24.50 = 10x + y

Using those two equations we see the following:

Mike paid $10.5 more for 5 more km. The initial fee remains unchanged, so we can calculate the rate for 1km, which is 10.5/5=2.1.

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Km travelled times 2.1 (the rate for 1km) plus 3.5 (the initial fee).

12*2.1 + 3.5 = 28.3

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Answer:

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Answer:

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Step-by-step explanation:

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