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Shtirlitz [24]
3 years ago
7

Suppose that you live in a community that has 125,000 households. Among these households, 50,000 have traditional landline telep

hones while the remaining 75,000 only use cellular and / or VOIP telephones. We are going to select 100 households from your community at random without replacement. The first household selected does not have a traditional landline telephone. What is the probability that the second household selected will have a traditional landline telephone
Mathematics
1 answer:
DedPeter [7]3 years ago
6 0

Answer:

0.4 = 40% probability that the second household selected will have a traditional landline telephone

Step-by-step explanation:

A probability is given by the number of desired outcomes divided by the number of total outcomes.

We have that:

125,000 households

50,000 have traditional landlines telephones.

The first household selected does not have a traditional landline telephone.

Now we have 125000 - 1 = 124,999 households, and 50,000 have traditional landlines telephones.

What is the probability that the second household selected will have a traditional landline telephone

p = \frac{50000}{124999} = 0.4

0.4 = 40% probability that the second household selected will have a traditional landline telephone

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There are 5 pens in a container on your desk. Among them, 3 will write well but 2 have defective ink cartridges. You will select
Norma-Jean [14]

Answer:

Kindly check explanation

Step-by-step explanation:

Total Number of pens = 5

Number of defective pens = 2

Number of non-defective pens = 3

A.) number of defective pens selected :

X : {0, 1, 2}

It is possible that no defective pen will be selected ; 1 defective will be chosen or both pens are defective.

2.)

Defective as Success (since selecting a defective pen is the point of interest.

3.)

Since selection is done without replacement

Probability of success per selection is different for each selection ;

Number of defective = 2

Number of observations = 5

P(success on first selection) = 2/5

P(success on second selection) = 1/4

Hence, X is not well approximated by a binomial random variable.

4.) if selection is done with replacement ; then then the probability of success per selection will be the Same for each selection made. Hence, X will be well approximated by a binomial Random variable.

5.) If sampling is done without replacement, then the the hypergeometric function will be a more effective approximation.

7 0
3 years ago
3. In a single growing season at the Smith Family Orchard, the average yield per apple tree is 150 apples when the number of tre
g100num [7]

Answer:

<em><u>A.10000</u></em>

<em><u>B.25 more trees must be planted</u></em>

Step-by-step explanation:

⇒Given:

  • The intial average yield per acre y_{i} = 150
  • The initial number of trees per acre  t_{i} = 100
  • For each additional tree over 100, the average yield per tree decreases by 1 i.e , if the number trees become 101 , the avg yield becomes 149.
  • Total yield = (number of trees per acre)*(average yield per acre)

<em>A.</em>

⇒If the total trees per acre is doubled , which means :

total number of trees per acre t_{f} = 2*t_{i} = 200

the yield will decrease by : t_{f} - y_{i}

y_{f}= 150-100= 50

⇒total yield = 50*200=10000

<em>B.</em>

⇒to maximize the yield ,

let's take the number of trees per acre to be 100+y ;

and thus the average yield per acre = 150 - y;

total yield = (100+y)*(150-y)\\=15000+50y-y^{2} \\

this is a quadratic equation. this can be rewritten as ,

     ⇒   =15000+50y-y^{2}\\=15000+625 - (625 - 50y +y^{2})\\=15625 - (y-25)^{2}

In this equation , the total yield becomes maximum when y=25;

<u><em>⇒Thus the total number of trees per acre = 100+25 =125;</em></u>

                 

3 0
3 years ago
A baseball coach order hats for his team. Each hat cost $10. The shipping charger is $6. The total cost of the order must be les
NeTakaya
The answer should be:

10h + 6 < 125
3 0
3 years ago
Read 2 more answers
A man gained rs. 3000 by selling a mobile set allowing 15 % discount on the marked price the loss would be rs. 8000. Find the ma
irinina [24]

Answer:

Marked price is Rs. 53333.33 and the cost price is Rs. 42333.33.

Step-by-step explanation:

Let Rs. x and Rs. y are the cost price and marked price of the mobile set respectively.

Now, the man has a loss of Rs. 8000 after giving a 15% discount on the marked price.

Therefore, 15% of y is 8000 i.e. 8000 = \frac{y\times 15}{100}

⇒ y = Rs. 53333.33

Now, the man gained Rs. 3000 by selling the mobile set allowing 15% discount on the marked price.

Therefore, the mobile set has the cost price = x = Rs. [(53333.33 - 8000) - 3000] = Rs. 42333.33 (Answer)

3 0
3 years ago
What is the 11th term of the geometric sequence 3,6,12,24,…?
Mamont248 [21]

Answer:

The 11th term is 3072.

Step-by-step explanation:

First, find the common ratio and the first term. The common ratio is 6/3 or 2. The first term is 3.

Use the direct formula, xi=a*r^i-1, to find the eleventh term. a is first term, and i is the index or the number of the term.

Substitute: x11=3*2^(11-1)

Or x11=3*2^10

So x11 is 3072

5 0
3 years ago
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