Yes. As long as it is linear, it will be continuous no matter the numbers. Now, I have no idea what a "real" number is, but I hope this helped.
Answer:
b
Step-by-step explanation:
Answer:
N=115
Step-by-step explanation:
n=.25(2.5715/.12)^2 =114.8 so round up to 115. Hope that help you
Answer: it’s very good imo
Answer:
f^-1(-32)=6
Step-by-step explanation:
<u>Find the inverse of the function f(x)=4-6x:</u>
f(x)=4-6x
y=4-6x
x=4-6y
x-4=-6y
(x-4)/-6=y
-1/6x+2/3=y
y=-1/6x+2/3
f^-1(x)=-1/6x+2/3
<u>Plug in f^-1(-32) for f^-1(x) and simplify:</u>
f^-1(-32)=-1/6(-32)+2/3
f^-1(-32)=16/3+2/3
f^-1(-32)=18/3
f^-1(-32)=6
