Answer:
9
Step-by-step explanation:
Area is measured in square units. For example in the rectangle above, if the sides are 2 and 4 meters long, then the area is 8 square meters. If the sides were 2 feet and 4 feet long the area would be 8 square feet. The most important thing to remember when calculating area is that.
Answer:
Option A is correct, i.e. 12.
Step-by-step explanation:
Given is the table of x&y relationship which represents an exponential function.
The average rate of change for a function can be found using the following formula:-
F_average = { f(b) - f(a) } / (b-a)
Given a = 3 and b = 5.
From the table, f(3) = 8 and f(5) = 32.
So, F_average = (32-8)/(5-3)
F_average = 24/2 = 12.
Hence, option A is correct, i.e. 12.
Answer:
D. The independent variable is the number of ticket price increases, and the dependent variable is the ticket sales.
Step-by-step explanation:
The wording, "the table shows A <em>with respect to</em> B" means that "B" is the independent variable. Here, "B" is "the number of times they have increased the price of the ticket." That is ...
the independent variable is the number of ticket price increases
5 points not 10 but
5/8 each day
5 days=5 times 5/8=5/1 times 5/8=25/8=24/8+1/8=3+1/8=3 and 1/8
3 and 1/8 mile
Answer:
Tn = 2Tn-1 - Tn-2
Step-by-step explanation:
Before we can generate the recursive sequence, we need to find the nth term of the given sequence.
nth term of an AP is given as:
Tn = a+(n-1)d
If a17 = -40
T17 = a+(17-1)d = -40
a+16d = -40 ...(1)
If a28 = -73
T28 = a+(28-1)d = -73
a+27d = -73 ...(2)
Solving both equations simultaneously using elimination method.
Subtracting 1 from 2 we have:
27d - 16d = -73-(-40)
11d = -73+40
11d = -33
d = -3
Substituting d = -3 into 1
a+16(-3) = -40
a - 48 = -40
a = -40+48
a = 8
Given a = 8, d = -3, the nth term of the sequence will be
Tn = 8+(n-1) (-3)
Tn = 8+(-3n+3)
Tn = 8-3n+3
Tn = 11-3n
Given Tn = 11-3n and d = -3
Tn-1 = Tn - d... (3)
Tn-1 = 11-3n +3
Tn-1 = 14-3n
Tn-2 = Tn-2d...(4)
Tn-2 = 11-3n-2(-3)
Tn-2 = 11-3n+6
Tn-2 = 17-3n
From 3, d = Tn - Tn-1
From 4, d = (Tn - Tn-2)/2
Equating both common difference
(Tn - Tn-2)/2 = Tn - Tn-1
Tn - Tn-2 = 2(Tn - Tn-1)
Tn - Tn-2 = 2Tn-2Tn-1
2Tn-Tn = 2Tn-1 - Tn-2
Tn = 2Tn-1 - Tn-2
The recursive formula will be
Tn = 2Tn-1 - Tn-2
