Answer:
Step-by-step explanation:
Given
--- Initial Amount
every 10 years
Required
The remaining amount after 300 years
To do this, we make use of:
Where
r = decay rate
T = the period of decay
In 300 years, there are 30 periods of 10 years.
i.e.
(-9) - (-2) = -7
that should be the answer you subtract
H = -2r + s/πr
C = 3A-a-b
If you need step by step comment
Answer: P=130
2W +2L=130
2(31) + 2(34)=130
W=31
L=34
Step-by-step explanation:
P=130
2L + 2W
W=L-3
Add all of the sides together to get perimeter.
2(L-3) + 2L=130
2L-6+2L=130
4L-6+6=130+6
4L=136
4L/4=136/4
L=34
W=L-3
W=34-3
W=31
by solving the first equation you'll get x= -24/13
if you solve the second option (B) then you'll the same result i.e x=-24/13
so option C is correct
