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3 years ago

Help me with this math problem

Mathematics

2 answers:

PSYCHO15rus [73]3 years ago

8 0

K^2+5=-6k
divide k = divide k
k+5=-6 then subtract 5 from each side of the equation
-5 = -5
k=-11

vlabodo [156]3 years ago

3 0

Move all terms to the left side then set equal to 0. then set each factor equal to 0. k=-1, -5

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What is the median for the set of data 3.5 1 3 4

yawa3891 [41]

Answer:

3.5

Step-by-step explanation:

Test Scores

1, 1, 2, 3, 3, 4, 4, 5, 5, 5

median(middle #)

(3+4)/2 = 7/2 = 3.5

6 0

3 years ago

Read 2 more answers

What is the slope line perpendicular to the equation 4x+3y=9

aleksandrvk [35]

Answer:

m=3/4

Step-by-step explanation:

first, let's put the line 4x+3y=9 from standard form (ax+by=c) into slope-intercept form (y=mx+b)

we have the equation 4x+3y=9

subtract 4x from both sides

3y=-4x+9

divide by 3

y=-4/3x+3

perpendicular lines have slopes that are negative and reciprocal. If the slopes are multiplied together, the result is -1

so to find the slope of the line perpendicular to the line y=-4/3x+3, we can take the slope of y=-4/3x+3 (-4/3) multiply it by a variable (this is our unknown value), and have that set to -1

(m is the slope value)

-4/3m=-1

multiply by -3/4

m=3/4

therefore the slope of the perpendicular line is 3/4

hope this helps!! :)

7 0

3 years ago

A water storage tank has the shape of a cylinder with diameter 14 ft. It is mounted so that the circular cross-sections are vert

andrezito [222]

Answer:

percentage of the total capacity is 75.6%

Step-by-step explanation:

Hello! To solve this problem we follow the following steps

1. draw the complete scheme of the problem (see attached image)

2. To solve this problem we must find the area of the circular sector using the following equation.(c in the second attached image)

$A=\frac{R^2}{2} (\alpha -sin\alpha )$

$\alpha =2arccos(\frac{d}{R})$

3. observing the attached images we replace the values in the equations and find the area of the circular sector, remember that you must transform the angle to radians

$\alpha =2arccos(\frac{5}{7})=88.83$

$A=\frac{R^2}{2} (\alpha -sin\alpha )\\A=\frac{7^2}{2} (88.83-sen88.83)*\frac{\pi rad}{180} =37.57ft^2$

4.we calculate the area of the total circle (At), then subtract the area of the circular sector (Ac) to find the area occupied by water (Aw)

$At=\frac{\pi }{4} (14ft)^2=153.93ft^2$

Aw=At-Ac=153.93-37.57=116.36ft^2

5.Finally, we calculate the percentage that represents the water in the tank by dividing the area of the water over the total area of the tank

$\frac{116.36}{153.93} *100=75.6$

percentage of the total capacity is 75.6%

3 0

3 years ago

Complete equation of the line through (1,4) and (2,2)

lions [1.4K]

Answer:

y = -2x + 6

Step-by-step explanation:

y=mx + c

m is the gradient and c is the y intercept

m = (y 2 - y 1) / (x 2 - x 1) = (2-4) / ( 2-1) = -2

y= -2x + c

To find c, just sub one of the coordinates into the eqn:

By using the coordinates (1,4)

4 = -2(1) + c

c = 6

Therefore, the equation is y = -2x + 6

3 0

3 years ago

determine whether the lines intersect and if so find the point of intersection and the cosine of the angle of intersection x=4t+

Fittoniya [83]

Answer:

As the lines are not intersecting nor parallel, they must be skew.

Step-by-step explanation:

Question is incomplete, we consider the nearest match available online.

Parametric equations of two lines are:

L₁ : x=4t+2 , y = 3 , z =-t+1

L₂: x=2s+2 , y= 2s+5 , z = s+1

If lines are parallel then parametric coordinates must be equal scalar multiple of each other which s not true here.

$4t+2=2s+2 ---(1)\\ \\3=2s+5---(2) \\\\-t+1=s+1---(3)$

If lines are intersecting then parametric coordinates must be equal for some value of t and s.

$From (3)\\-t=s\\From (2)\\\\s=\frac{3-5}{2}\\\\s=-1\\\implies t=1\\\\To\,\,check\,\, the \,\,values \,\,of \,\,s\,\, and \,\,t \,\,for\,\,intersection\,\,put \,\,them\,\, in\,\, (1)\\\\4(1)+2= 2(-1)+2\\ 6\ne0$

Hence the lines are not intersecting nor parallel, they must be skew.

6 0

3 years ago