All categories

3 years ago

A man can run a mile in 4 minutes. calculate his average speed in kilometers per hour. show your work. (1 mile = 1.61 km)

Mathematics

1 answer:

elena55 [62]3 years ago

7 0

1 mile =1.61km

60 minutes per hour

60/4 = 15 ( he can run 15 miles in one hour)

15 x 1.61 = 24.15 km per hour

round your answer if needed

You might be interested in

BRAINIEST ANSWER <br> FIND THE VOLUME AND ROUND TO THE NEAREST TENTH :))) <br> Please help

kolezko [41]

Answer: 3,150 ft.

Step-by-step explanation: multiply all sides together

3 0

3 years ago

Let f(x) = ............

34kurt

Answer:

So first lets find g(-1)

so we plug in the answers:

-2 * -1 ^2 -4

-2*1-4 = -2-4 =

-6

Now lets solve for f(-2)

-2^2-3

4-3=1

-6+1 = 5

3*5 = 15

Im getting answer of 15 but it shows -15 or something, so I dont know if I got it wrong or if its like a dash then the answer.

3 0

3 years ago

Pleaseeee helpppp!!!!

ANTONII [103]

Answer:

The easiest way to do this is to reflect Figure I over the Y axis. Then move it up 3 and left 2.

5 0

4 years ago

Read 2 more answers

Eva's bedroom rug is 2 3/4 ft long and 2 1/2 ft wide what is the area of the rug

den301095 [7]

Exact Form: 55/8
Decimal: 6.875
Mixed Number: 6 7/8

5 0

3 years ago

Read 2 more answers

A spherical balloon is being inflated at a rate of 3 cubic inches per second. Determine the change in the rate of the radius.How

Novay_Z [31]

Answer:

The rate rate of change of radius is $\frac{1}{48\pi}$ inches per second when the diameter is 12 inches.

The radius is changing more rapidly when the diameter is 12 inches.

Step-by-step explanation:

Consider the provided information.

A spherical balloon is being inflated at a rate of 3 cubic inches per second.

The volume of sphere is $V=\frac{4}{3}\pi r^3$

Differentiate the above formula with respect to time.

$\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}$

Substitute the respective values in the above formula,

$3=4\pi 6^2\frac{dr}{dt}$

$\frac{1}{48\pi}=\frac{dr}{dt}$

The rate rate of change of radius is $\frac{1}{48\pi}$ inches per second when the diameter is 12 inches.

When d=16

$3=4\pi 8^2\frac{dr}{dt}$

$\frac{3}{256\pi}=\frac{dr}{dt}$

Thus, the radius is changing more rapidly when the diameter is 12 inches.

5 0

3 years ago