Question

Point T is on line segment S U ‾ SU . Given T U = x − 1 , TU=x−1, S U = 3 x − 7 , SU=3x−7, and S T = x + 7 , ST=x+7, determine the numerical length of T U

Answer 1

Answer:

TU = 12

Step-by-step explanation:

Given

TU = x − 1

SU = 3x − 7

ST = x + 7

TU = ?

Then we can say that

SU = ST + TU

⇒  3x − 7 = (x + 7) + (x − 1)

⇒  3x − 7 = 2x + 6

⇒  x = 13

Finally, we get

TU = x − 1

⇒  TU = 13 - 1

⇒  TU = 12

Therefore,

ST = x + 7 = 13 + 7 = 20

SU = 3x − 7 = 3*(13) - 7 = 32