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Marrrta [24]
2 years ago
7

Select the locations on the number line to plot the points 2, 1, and −4 .

Mathematics
2 answers:
Aliun [14]2 years ago
8 0

Step-by-step explanation:

look at the picture

hope it helps you.

rodikova [14]2 years ago
5 0

Answer:

-5-4-3-2-1 0 1 2 3 4 5

Step-by-step explanation:

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Maria has 64 flowers she makes 8 bouquets with the flowers how many bouquets of flowers will she have if she has 80 flowers
Pepsi [2]
The ratio of flowers to bouquets is

64:8

With 80 flowers, the ratio would be

80:x

so...

64:8 divide each by 8 to get 8:1

multiply each by 10 to get

80:10

10 bouquets
8 0
3 years ago
Read 2 more answers
Which of these is a synonym of 'closing sentence"? *
Sophie [7]

Answer:

conclusion because you are concluding eveything you said in the paragraph before.

4 0
3 years ago
What is the range of the function f(x) = 3x2 + 6x – 8?
timama [110]

Answer:

Range is {y | y ≥ –11}


Step-by-step explanation:

This is quadratic equation.

<em>A quadratic equation's range can be found if we find the vertex.</em>

For quadratic equations that have a positive number in front of  x^{2} , it is upward opening and thus <u>all the numbers greater than or equal to the minimum value of vertex is the range.</u>


The formula for vertex of a parabola is:

Vertex =  (-\frac{b}{2a}, f(-\frac{b}{2a})

Where,

  • a is the coefficient of x^{2}
  • b is the coefficient of x

From our equation given, a=3  and  b=6

Now, x coordinate of vertex is  x=-\frac{b}{2a}\\x=-\frac{6}{(2)(3)}\\x=-\frac{6}{6}\\x=-1

y coordinate of the vertex IS THE MINIMUM VALUE that we want. We get this by plugging in the x value [ x=-1 ] into the equation. So we have:

3(-1)^{2}+6(-1)-8\\=-11


Hence, the range would be all numbers greater than or equal to -11  

Third answer choice is the right one.


6 0
2 years ago
Read 2 more answers
5 points
jonny [76]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

y = \stackrel{\stackrel{m}{\downarrow }}{2}x-5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so we're really looking for the equation of a line whose slope is 2 and passes through (4 , -3)

(\stackrel{x_1}{4}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{2}(x-\stackrel{x_1}{4}) \\\\\\ y+3=2x-8\implies y=2x-11

5 0
2 years ago
In the function y-1 = (4x)² + 7, what effect does the number 4 have on
bija089 [108]

Answer:

D. It shrinks the graph horizontally to 1/4 the original width.

Step-by-step explanation:

f(px): |p|>1 horizontal compression   (x,y) -> (x/p , y)

8 0
3 years ago
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