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kondaur [170]
3 years ago
5

Plz help ill give you brainlist

Mathematics
1 answer:
SpyIntel [72]3 years ago
7 0
2πr= 2* 3.14*20=125.6
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Jan has 44 apples and tim has 76 home many apples all together
Lady bird [3.3K]
44
76
___
120
hope this helps you add

8 0
3 years ago
Read 2 more answers
Can someone help me with this problem ​
Alex_Xolod [135]

Answer:

<h2>A = 20</h2><h2>P = 6√10</h2>

Step-by-step explanation:

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A(-3, 0) , B(3, 2)

AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}

A(-3, 0), D(-2, -3)

AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

AB = CD and AD = BC

The area of a rectangle:

A=(AB)(AD)

Substitute:

A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20

The perimeter of a rectangle:

P=2(AB+AD)

Substitute:

P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}

4 0
3 years ago
What is the value of k if the line 5x+ky=12 passes through the point (2,-1).
olchik [2.2K]

Answer:

k = -2

Step-by-step explanation:

1. Substitute the point (2,-1) into the given equation 5x+ky=12. The first number is 2, the x-value. The second number is -1, the y-value.

5x + ky = 12

5(2) + k(-1) = 12

2. Simplify

5(2) + k(-1) = 12

10 + (-k) = 12

10 - k = 12

2. Isolate k

10 - k = 12

-k = 12-10

-k = 2   <= here multiply both sides by (-1)

k = -2

5 0
3 years ago
Convert 3.212121… into a fraction using variable
seraphim [82]

Answer:

In fraction it is

\frac{3212121}{1000000}

<h2>#NoNeedFriends</h2>
3 0
2 years ago
Read 2 more answers
If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a
galina1969 [7]

Answer:

<em>Both objects collide at t=3 in the point  <9,9,9></em>

Step-by-step explanation:

<em>Collision Of Moving Objects </em>

Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.

The positions of two object are given as

r1(t)=

r2(t)=

Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both

t^2=4t-3

Rearranging

t^2-4t+3=0

Factoring

(t-1)(t-3)=0

We found two solutions

t=1,\ t=3

for t=1 the x-coordinates are

x1=t^2=1

x2=4t-3=1

For t=3

x1=t^2=9

x2=4t-3=9

Now we'll test both values in the y-coordinates

y1=7t-12

y2=t^2

For t=1

y1=-5

y2=1

Thus they don't collide at t=1. Let's try t=3

y1=7(3)-12=9

y2=3^2=9

Now let's try the z-coordinate for t=3

z1=t^2=9

z2=5t-6=9

Since the three coordinates match, we can say both objects collide at t=3 in the point  <9,9,9>

6 0
3 years ago
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