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iris [78.8K]
2 years ago
6

HELP ASAP f(x)=x² what is g(x)?

Mathematics
1 answer:
murzikaleks [220]2 years ago
4 0

Just by comparing the plots of f(x) and g(x), it's clear that g(x) is just some positive scalar multiple of f(x), so that for some constant k, we have

g(x) = k • f(x) = kx² = (√k x)²

The plot of the transformed function g(x) = (√k x)² passes through the point (1, 4), which means

g(1) = (√k • 1)² = 4

and it follows that k = 4. So g(x) = 4x² = (2x)² and B is the correct choice.

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-3(4u-v)-5(-v+3u)<br> For 20 points
natita [175]

Answer:

−27u + 8v

Explanation:

−3(4u − v) − 5( − v + 3u)

[ Distribute ]

= (−3)(4u) + (−3)(−v) + (−5)(−v) + (−5)(3u)

= −12u + 3v + 5v + −15u

[ Combine Like Terms ]

= −12u + 3v + 5v + −15u

= (−12u + −15u) + (3v + 5v)

= −27u + 8v

- PNW

4 0
3 years ago
Read 2 more answers
If 36 is 90% of a value, what is that value?
fredd [130]
The value of 36 is 90% is 40.

6 0
3 years ago
Find the volume for the shape below
Thepotemich [5.8K]
30in I know that because I just did this .this is EASY!
4 0
2 years ago
The prime factors of a number are 2, 2, 2, and 5. What is the number?
fgiga [73]

Answer: 40

Step-by-step explanation:

Since 40 could be = 1 x 40, 2 x 20, 4 x 10, or 5 x 8.

The Factors of 40 will therefore be: 1, 2, 4, 5, 8, 10, 20, 40.

The Prime factor then is: 2, 2, 2, 5

Multiplying them together gives 40.

7 0
3 years ago
Given the Arithmetic series A1+A2+A3+A4 7 + 11 + 15 + 19 + . . . + 91 What is the value of sum?
aivan3 [116]

Answer:

The value of the sum is 1078

Step-by-step explanation:

* Lets revise how to find the sum of the arithmetic series

- In the arithmetic series there is a constant difference between each

 two consecutive terms

- Ex:

# 4 , 9 , 14 , 19 , 24 , .......... (+ 5)

# 25 , 15 , 5 , -5 , -15 , .......... (-10)

- So if the first term is a and the constant difference between each two

  consecutive terms is d, then

  U1 = a , U2 = a + d , U3 = a + 2d , U4 = a + 3d , ..........

- Then the nth term is Un = a + (n - 1)d

- The sum of n terms is Sn = n/2[a + L] , where L is the last term in

 the series

* Lets solve the problem

∵ The arithmetic series is 7 + 11 + 15 + 19 + ......................... + 91

∴ The first term (a) is 7

∴ The last term is (L) 91

- Lets find the constant difference

∵ 11 - 7 = 4 and 15 - 11 = 4

∴ The constant difference (d) is 4

- Lets find the sum of the series from 7 to 91

∵ Sn = n/2[a + L]

∵ a = 7 and L = 91

∴ Sn = n/2[7 + 91]

- We need to know how many terms in the series

∵ L is the last term and equals 91 lets find its position in the series

∵ Un = a + (n - 1)d

∵ a = 7 , d = 4 and Un = 91

∴ 91 = 7 + (n - 1)(4) ⇒ subtract 7 from both sides

∴ 84 = (n - 1)(4) ⇒ divide both sides by 4

∴ 21 = n - 1 ⇒ add 1 to both sides

∴ n = 22

∴ The number of the terms in the series is 22

- Lets find the sum of the 22 terms (S22)

∴ S22 = 22/2[7 + 91]

∴S22 = 11[98] = 1078

* The value of the sum is 1078

4 0
3 years ago
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