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Veronika [31]
3 years ago
13

I need help please and thank you no links

Mathematics
1 answer:
Phantasy [73]3 years ago
8 0

Answer:

5x-15=2x+21

5x-2x=21+15

3x=36

x=12

b= 45°

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Translate the sentence into an inequality.
lord [1]

Answer:

2(W - 5) ≤ -29      

Step-by-step explanation:

"Twice the difference of a number and 5 is at most -29" can be expressed symbolically as follows:

2(W - 5) ≤ -29      

Further explanations:

"the difference of a number and 5" is W - 5, and thus "Twice the difference of a number and 5" is 2(W - 5).

"x ≤ -29" states "x is at most -29."

7 0
2 years ago
You are at the bottom of a mountain where the temperature is 74°F. The top of the mountain is 5500 feet above you. What is the t
KIM [24]

F<span>or every 1,000 feet you go up in elevation</span>, <span>the temperature decreases by about 3.3°F</span>

 

Given:

Temperature at the bottom of the mountain is 74°F

The top of the mountain is 5500 feet above you

 

Change (reduction) in temperature is 3.3 X 5500 / 1000

= 18.15°F

 

Temperature at the top of the mountain is 74°F – 18.15°F

= 55.85°F

6 0
3 years ago
Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a
spin [16.1K]

Answer:

Mean = 68.9

s^2 =18.1 --- Variance

Step-by-step explanation:

Given

\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5

For 59 - 66

x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5

For 67 - 74

x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5

For 75 - 82

x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5

For 83 - 90

x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5

So, the table becomes:

\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}

The mean is then calculated as:

Mean = \frac{\sum fx}{\sum f}

Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}

Mean = \frac{2547.5}{37}

Mean = 68.9 -- approximated

Solving (b): The sample variance:

This is calculated as:

s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}

So, we have:

s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}

s^2 =\frac{652.8}{36}

s^2 =18.1 -- approximated

5 0
2 years ago
Dentify the type of variation given and the constant of variation (k)
velikii [3]
The constant variation k is 12
3 0
3 years ago
On a unit circle, the vertical distance from the x-axis to a point on the perimeter of the circle is twice the horizontal distan
zalisa [80]

Answer:

(2√5)/5

Explanation:

CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLATION

From the question we can deduced that the vertical distance from the x-axis to a point on the perimeter of the circle is twice the horizontal distance, we can say that the y-coordinate, is twice of the horizontal, then let call the horizontal "y", the vertical would be 2y.

from the attachment the question on the unit circle is interpreted using a figure,then, hypotenuse was first calculated

4 0
2 years ago
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