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S_A_V [24]
3 years ago
12

Which equation has infinitely many solutions? A) 4x + 3 3 = 4x + 5 B) 10x + 8 2 = 5x + 4 C) 8x − 5 3 = 2x − 2 D) 8x − 5 2 = 4x −

6
Mathematics
1 answer:
abruzzese [7]3 years ago
3 0

Answer: If the left side and the right side of the equation are equal, the equations has  infinitely many solutions.

Step-by-step explanation:

The options are not clear, so I will give  you a general explanation of the procedure you can use to solve this exercise.

The Slope-Intercept form of the equation of a line is the following:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

For this exercise you need to remember that, given a System of Linear equations, if they are exactly the same line, then the System  of equations has Infinitely many solutions.

If you  have the following system:

\left \{ {{y=2x+1} \atop {y=\frac{12}{6}x+1}} \right.

You can simplify the second one:

y=2x+1

Then, both equations are the same line.

By definition you can also write the systemf making both equations equal to each other:

2x+1=2x+1

So, if the left side and the right side are equal, the equations has  infinitely many solutions.

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P(Girl Sophomore) :<br> =[?]
marusya05 [52]

Probability helps us to know the chances of an event occurring. The probability being a Sophomore given she is a girl is 1/3.

<h3>What is Probability?</h3>

Probability helps us to know the chances of an event occurring.

\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}

The probability of being a girl and Sophomore is 9/37. While the probability of being a girl is 27/37. Therefore, the probability being a Sophomore given she is a girl is,

P(Girl l Sophomores) = P(Girl and Sophomore)/ P(Girl)

                                  = (9/37) / (27/37)

                                  = 9 / 27

                                  = 1/3

Hence, the probability being a Sophomore given she is a girl is 1/3.

Learn more about Probability:

brainly.com/question/795909

#SPJ1

3 0
1 year ago
Read 2 more answers
How to find cp if loss and sp are given​
velikii [3]

Step-by-step explanation:

\tt{ \: H \: E \: Y \: \:  T \: H \: E \: R\: E \: } !

When Loss and Selling price ( SP ) are given , Cost price ( CP ) can be found out using the following formulae :

✰ \large{ \boxed{ \boxed{ \tt{CP = Loss + SP}}}}

\text{How \: did\: we \:get  \:the \: formula :  \: CP \:  = Loss \:  +  \: SP} \: ?

We simply derived the formula from Loss = CP - SP.

First , Swap the sides of the equation :

⟶ \text{CP - SP = Loss}

Move SP to right hand side and change it's sign :

⟶\text{CP = Loss + SP}

This is how , CP can be obtained when we are given loss and SP.

Hope I helped ! ♡

Have a wonderful day / night ! ツ

# \underbrace{ \tt{C \: a \: r \: r \: y \:  \: O \:n \:  \: L \: e \: a \: r \: n \: i \: n \: g}} !!

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

8 0
3 years ago
list the pair of congruent angles and the extended proportion that relations the corresponding sides for the similar polygons KL
kherson [118]

Answer:  

In Polygons KLMNP and HGFDC,

Angles K, L, M, N and P are corresponding to H, G, F, D and C,

And, Sides KL, LM, MN, NP and PK are corresponding to sides HG, GF, FD, DC and CH

If the two figures are similar then their corresponding sides and angles are congruent.

Therefore, If  Polygon KLMNP is similar to HGFDC,

Then, ∠ K ≅ ∠ H,  ∠ L ≅ ∠ G,  ∠ M ≅ ∠ F,  ∠ N ≅ ∠ D,   ∠ P ≅ ∠ C

And, KL ≅ HG,  LM ≅ GF,  MN≅FD,  NP≅DC,  PK≅CH

7 0
3 years ago
Read The Question On The Following PNG
ipn [44]
A. Will most likely be the answer I might be wrong.
3 0
3 years ago
Read 2 more answers
Which of the following is an equivalent form of the compound inequality<img src="https://tex.z-dn.net/?f=%20%20-%2044%20%5C%20%2
Novay_Z [31]

Given the compound inequality:

-44>-2x-8⩾-8

Let's find the equivalent form of the inequality.

To find the equivalent form, let's simplify the inequality.

SInce it is a compund inequality, we are to seperate the inequalities.

Simplify the first two inequalities, then simplify the last two inequalities.

We have:

First two inequalities: -44 > -2x - 8

Last two inequalities: -2x - 8 ⩾ -8

Let's simplify both

\begin{gathered} -44>-2x-8 \\  \\ Rewrite\text{ the inequality and change the inequality sign:} \\ -2x-8\begin{gathered} \text{Second inequality:} \\ -2x-8⩾-8 \\  \end{gathered}

Therefore, the equivalent form is:

-2x-8

ANSWER:

d.\text{   -2x - 8

5 0
1 year ago
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