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3 years ago

Help and please explain!

Mathematics

1 answer:

UkoKoshka [18]3 years ago

4 0

Answer:

a. 146

Step-by-step explanation:

{4*[72-6*(3+2)]}-22

=[4*(72-6*5)]-22

=[4*(72-30)]-22

=(4*42)-22

=168-22

=146

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Translate to an algebraic expression <br><br> 49 increased by d what translation is

Nikitich [7]

49 increased by d is 49 + d but I feel that this isn't the whole statement...?

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3 years ago

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Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he

alexgriva [62]

Answer:

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

$9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$

$e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) } ]y = 0$

By comparing with y′+p(t)y=g(t), we get

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous.

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2 years ago

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3 years ago

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olchik [2.2K]

Answer:

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Step-by-step explanation:

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3 years ago

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What is the value of x -6/7=-x/84?

AURORKA [14]

Answer:

x = 72 / 85

Step-by-step explanation:

x -6/7=-x/84

x + x/84 = 6/7

84/84x + 1/84x = (12*6) / (12*7)

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84/85 * { 85/84 } * x = 84/85 * { ( 72 ) / ( 84 ) }

{ (84 * 85) / ( 85 * 84) } * x = ( 84 * 72 ) / ( 85 * 84 )

(7140) / ( 7140) * x =. ( 6048 ) / ( 7140)

x = 6048 / 7140

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3 years ago