Answer:
(a) The number of shoes that Marquise has is 40 pairs of shoes
(b) The number of pairs of shoes that Bron'Tavious has is 20 pairs of shoes
(c) The number of pairs of shoes that JayDarius has is 35 pairs of shoes
Step-by-step explanation:
The given information are;
The number of shoes that Marquise has = 2 × The number of pairs of shoes that Bron'Tavious
The number of pairs of shoes that JayDarius has = The number of pairs of shoes that Bron'Tavious + 15
The total number of pairs of shoes they have all together = 95 pairs of shoes
Let the number of pairs of shoes that Bron'Tavious has = X. Therefore, we have;
The number of shoes that Marquise has = 2 × X
The number of pairs of shoes that JayDarius has = X + 15
The total number of pairs of shoes they have all together = X + X + 15 + 2 × X = 95
X + X + 15 + 2 × X = 95
4 × X + 15 = 95
4 × X = 95 - 15 = 80
X = 80/4 = 20
∴ X = 20
(a) The number of shoes that Marquise has = 2 × X = 2 × 20 = 40
The number of shoes that Marquise has = 40 pairs of shoes
(b) The number of pairs of shoes that Bron'Tavious has = X = 20
The number of pairs of shoes that Bron'Tavious has = 20 pairs of shoes
(c) The number of pairs of shoes that JayDarius has = X + 15 = 20 + 15 = 35
The number of pairs of shoes that JayDarius has = 35 pairs of shoes.
