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bekas [8.4K]
3 years ago
8

Please help and thank you

Mathematics
2 answers:
Kipish [7]3 years ago
8 0
<h2>Answer:</h2>

<u>The right choice is</u><u> C</u>

<h2>Step-by-step explanation:</h2>

See the image

asambeis [7]3 years ago
3 0

Answer:

A should be the correct answer

Step-by-step explanation:

1/3π xr^2xh just means "3.14 x r^2 x height ÷ 3"

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Sorry I don't know anything about that!
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6 0
3 years ago
Read 2 more answers
Please help me if u can!!​
damaskus [11]

Answer:

89 kids are in the 3 rd grade

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
onji has $5.25 in nickels and dimes.The coin value can be modeled by the equation 0.10d + 0.05n = 5.25, where d represents the n
Maru [420]
This is how you solve this problem:
.10d + .05n = 5.25

(plug in the number of dimes we have)

(21 x .1) + .05n = 5.25

(multiply number of dimes x value of the dime)

2.10 + .05n = 5.25

(subtract 2.10 from both sides)

.05n = 3.15

(divide both sides by .05 to get the number of nickels)

n = 63 nickels

Hope this helps!

3 0
3 years ago
Please help, ty if you do :D
Dennis_Churaev [7]

Answer:

Your Answer is going to be C

3 0
3 years ago
3. Try It #3 Write the point-slope form of an equation of a line with a slope of -2 that passes through the point (-2,2). Then r
vova2212 [387]

Answer:

Point-slope form of equation given as $y-2=-2(x+2)$.

Slope-intercept form of equation is given as $y=-2 x-2$.

Step-by-step explanation:

In the question, it is given that the slope of a line is -2 and it passes from (-2,2).

It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.

To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.

Step 1 of 2

Passing point of the line is (-2,2).

Hence, $x_{1}=-2$ and

$$y_{1}=2 \text {. }$$

Also, the slope of the line is -2.

Hence, m=-2

Substitute the above values in point-slope form of equation given by $y-y_{1}=m\left(x-x_{1}\right)$

$$\begin{aligned}&y-y_{1}=m\left(x-x_{1}\right) \\&y-2=-2(x-(-2) \\&y-2=-2(x+2)\end{aligned}$$

Hence, point-slope form of equation given as y-2=-2(x+2).

Step 2 of 2

Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.

$$\begin{aligned}&y-2=-2(x+2) \\&y-2=-2 x-4 \\&y=-2 x-4+2 \\&y=-2 x-2\end{aligned}$$

Hence, slope-intercept form of equation is given as y=-2x-2.

7 0
2 years ago
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