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drek231 [11]
3 years ago
15

16 divided by 6.08 . 2 digit divisors

Mathematics
2 answers:
astra-53 [7]3 years ago
7 0
The answer is 22.08 you just have to dived
ratelena [41]3 years ago
5 0
Lastly, 16<span> goes into 128 exactly 8 times, and the division is over.  </span>2<span>. </span>Divide<span>. First write a multiplication table for the </span>divisor<span>. Check each answer by multiplying.</span>
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Together Dean and Angelo have 185 stamps. Dean's collection has 57 more stamps than Angelo's collection. How many stamps does An
marta [7]
First you would do 185-57 which gets you 128 next divide it by 2 which gets you 64 so Angelo has 64 and Dean has 121 stamps and together they have a total of 185
7 0
3 years ago
Yea lol how do u do this
seropon [69]
Hello!!

So what they are giving you is the x,y coordinate of the terminal side of an angle. Meaning 4,10 is the point x=4 and y= 10.
So if we have that, then we can solve for the quadrant that the angle falls in. So for two positive values it tells us it falls in quad 1.

So we have x and y so now use x^2+y^2=h^2 to solve for hypotenuse.

So we get h=sqrt(4^2+10^2)= sqrt(116) or 2*sqrt(29).

Now knowing our trig identities.
Sin= y/h
Cos=x/h
Tan=y/x
Csc=h/y=1/sin
Sec=h/x=1/cos
Cot=x/y=1/tan

So now we have
X=4 Y=10 H=2*sqrt(29)

Now we just use the above identities and plug and chug for your answers. Doing the same one point(4,10)
Sin=10/2*sqrt(29)= (5*sqrt(29))/29
Cos=4/2*sqrt(29)= (2*sqrt(29))/29
Tan=10/4=5/2
Sec=2*sqrt(29)/10= sqrt(29)/5
Csc=2*sqrt(29)/4= 2*sqrt(29)/2
Cot=4/10= 2/5

Now do the same thing as above for all sets of your questions.

Hope this helps!! Any questions please just ask! Thank you so much!
3 0
3 years ago
A group of 25 employees want to go out for a group dinner.
SVEN [57.7K]
A is 18:25
B is 7:25
5 0
2 years ago
Evaluate the expression. If necessary, round to the nearest hundredth. ln 0
STatiana [176]
Well, a logarithmic expression is just an exponential expression written from the point of the exponent.

now, ln is just a shorthand for the logarithm with a base "e" or euler's constant, so-called the "natural logarithm", now, let's use the exponential version of that here, and let's say equals an constant exponent of "k",

\bf \textit{exponential form of a logarithm}\\\\&#10;log_{{  a}}{{  b}}=y \implies {{  a}}^y={{  b}}\qquad\qquad &#10;%  exponential notation 2nd form&#10;{{  a}}^y={{  b}}\implies log_{{  a}}{{  b}}=y\\\\&#10;-------------------------------\\\\&#10;ln(0)=k\implies log_e(0)=k\implies e^k=0

now, look closely, what "k" value, what exponent, negative or fraction or positive, will ever make "e" to 0?  none, so one can say is "undefined".
7 0
3 years ago
Can someone tell me how to do this ?
ElenaW [278]

i am not 100% sure but...

(4x+3)=47

<u>    - 3    - 3 </u>

     4x=44

44/4= 11

so x = 11

7 0
3 years ago
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