This question is incomplete
Complete Question
Consider greenhouse A with floor dimensions w = 16 feet , l = 18 feet.
A concrete slab 4 inches deep will be poured for the floor of greenhouse A. How many cubic feet of concrete are needed for the floor?
Answer:
96 cubic feet
Step-by-step explanation:
The volume of the floor of the green house = Length × Width × Height
We convert the dimensions in feet to inches
1 foot = 12 inches
For width
1 foot = 12 inches
16 feet = x
Cross Multiply
x = 16 × 12 inches
x = 192 inches
For length
1 foot = 12 inches
18 feet = x
Cross Multiply
x = 18 × 12 inches
x = 216 inches
The height or depth = 4 inches deep
Hence,
Volume = 192 inches × 216 inches × 4 inches
= 165888 cubic inches
From cubic inches to cubic feet
1 cubic inches = 0.000578704 cubic foot
165888 cubic inches = x
Cross Multiply
x = 16588 × 0.000578704 cubic foot
x = 96 cubic feet
Therefore, 96 cubic feet of concrete is needed for the floor
Answer: 1) D 2) B
<u>Step-by-step explanation:</u>
1) The denominator cannot equal zero, Factor the denominator to find the zeros. n³ - 4n² + 3n = 0
n(n - 3)(n - 1) = 0
n=0 n-3=0 n-1=0
n=0 n=3 n=1
2) In order to be a rational expression, it must be in the form 
where both a and b are integers.
Since 
is irrational and not an integer, then the expressions containing an irrational term <em>after simplified</em> cannot result in an integer.
Therefore, options <em>(i)</em> and <em>(iv)</em> are not rational expressions.
Option <em>(iii)</em> contains b as an exponent. Since there is no information about b, it could be a fraction, which means it could be an irrational number.
Step-by-step explanation:
When b = 5,
4b² = 4(5)² = 4 * 5 * 5 = 100.
Answer:
a. The mean of the sample is M=35.
The variance of the sample is s^2=39.125.
The standard deviation of the sample is s=6.255.
b. z=-1.6
c. SEM = 2.212
Step-by-step explanation:
The mean of the sample is M=35.
The variance of the sample is s^2=39.125.
The standard deviation of the sample is s=6.255.
<u>Sample mean</u>
<u />
<u>Sample variance and standard deviation</u>
<u />![s^2=\dfrac{1}{(n-1)}\sum_{i=1}^{8}(x_i-M)^2\\\\\\s^2=\dfrac{1}{7}\cdot [(27-(35))^2+(25-(35))^2+(32-(35))^2+(40-(35))^2+(43-(35))^2+(37-(35))^2+(35-(35))^2+(38-(35))^2]\\\\\\](https://tex.z-dn.net/?f=s%5E2%3D%5Cdfrac%7B1%7D%7B%28n-1%29%7D%5Csum_%7Bi%3D1%7D%5E%7B8%7D%28x_i-M%29%5E2%5C%5C%5C%5C%5C%5Cs%5E2%3D%5Cdfrac%7B1%7D%7B7%7D%5Ccdot%20%5B%2827-%2835%29%29%5E2%2B%2825-%2835%29%29%5E2%2B%2832-%2835%29%29%5E2%2B%2840-%2835%29%29%5E2%2B%2843-%2835%29%29%5E2%2B%2837-%2835%29%29%5E2%2B%2835-%2835%29%29%5E2%2B%2838-%2835%29%29%5E2%5D%5C%5C%5C%5C%5C%5C)
![s^2=\dfrac{1}{7}\cdot [(58.141)+(92.641)+(6.891)+(28.891)+(70.141)+(5.64)+(0.14)+(11.39)]\\\\\ s^2=\dfrac{273.875}{7}=39.125\\\\\\s=\sqrt{39.125}=6.255](https://tex.z-dn.net/?f=s%5E2%3D%5Cdfrac%7B1%7D%7B7%7D%5Ccdot%20%5B%2858.141%29%2B%2892.641%29%2B%286.891%29%2B%2828.891%29%2B%2870.141%29%2B%285.64%29%2B%280.14%29%2B%2811.39%29%5D%5C%5C%5C%5C%5C%09%09%09%09%09%09%09%09%09%09%09%09s%5E2%3D%5Cdfrac%7B273.875%7D%7B7%7D%3D39.125%5C%5C%5C%5C%5C%5Cs%3D%5Csqrt%7B39.125%7D%3D6.255)
b. If the population mean is 45, the z-score for M=35 would be:
c. The standard error of the mean (SEM) of this group is calculated as:
Answer:
C=pi(radius)^2
c=pi(5)^2
c=pi(25)
c=78.5398163397...
c is about 78.5
Step-by-step explanation:
