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Novosadov [1.4K]
3 years ago
6

Corey is 2 times older than Brad. If the sum of their ages is 54 how old is Corey?

Mathematics
1 answer:
lana66690 [7]3 years ago
3 0

Answer:

54/3=18 so Brad is 18 and Corey is 36

36 + 18 = 54

Step-by-step explanation:

If Corey is 2 times older then you divide by that number which is 2 + 1 so you divide by 3.

Hope this helps can I have brainliest

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​$9500 is​ invested, part of it at 12​% and part of it at 9​%. For a certain​ year, the total yield is ​$1032.00. How much was
alina1380 [7]
Let's say the quantities are "a" and "b"
so... whatever "a" and "b" are, they add up to 9,500, thus

a + b = 9,500

now, "a" was invested at 12%, or 12/100
it yielded some amount, actually 12% of a, or 12/100 * a or 0.12a

the "b" amount was invested at 9%, or 9/100
it yielded 9% of b, or 9/100 * b or 0.09b

whatever 0.12a is, and 0.09b is, their sum or total yield was 1032
thus
0.12a + 0.09b = 1032

thus     \bf \begin{cases}
a+b=9,500\implies \boxed{b}=9,500-a\\\\
0.12a+0.09b=1032\\
--------------\\
0.12a+0.09(\boxed{9,500-a})=1032
\end{cases}

solve for "a" to see how much was invested at 12%

what about "b"? well, b = 9500 - a
4 0
3 years ago
Combined 5 Z + 3 - 3 Z ​
Komok [63]

Answer:

Step-by-step explanation:

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4 0
3 years ago
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A test was given to a group of students. The grades and gender are summarized below
faust18 [17]

Answer:

<h3>★ <u>11/</u><u>3</u><u>0</u> is the right answer. ★</h3>

Step-by-step explanation:

  • Number of male students who got 'A' in the test is 11
  • Number of female students who got 'A' in the test is 19
  • Total students who got 'A' in the test is 30
  • Probability that the male student got an 'A' is P(A | male) = (Number of male students who got 'A' in the test)/(Number of total students who got 'A' in the test) = <em><u>11/</u></em><em><u>3</u></em><em><u>0</u></em>
4 0
3 years ago
Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre
andrew-mc [135]

Answer:

The area function is

A=\frac{135}{2}x-\frac{9}{2}x^2.

The domain and range of A is (0,15m) and (0, 253.125 m^2].

Step-by-step explanation:

The given length of fencing is 90 m.

Let the length and width of each pen be x and y respectively as shown in the figure.

As there are 3 pens, so, the total area,

A= 3 xy \;\cdots (i)

From the figure the total length of fencing is 6x+4y.

Here, for a significant area for the animals, x>0 as well as y>0 as x and y are the sides of ben.

From the given value:

6x+4y=90\;\cdots (ii)

\Rightarrow  y=\frac {45}{2}-\frac{3x}{2}

Now, from equation (i)

A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)

\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)

This is the required area function in the terms of variable x.

For the domain of area function, from equation (ii)

x=15-\frac{2y}{3}

\Rightarrow x [as y>0]

So, the domain of area function is (0,15m).

For the range of area function:

As x \rightarrow 0 or y\rightarrow 0, then A\rightarrow 0 [from equation (i)]

\Rightarrow A>0

Now, differentiate the area function with respect to x .

\frac {dA}{dx}=\frac{135}{2}-9x

Equate \frac {dA}{dx}  to zero to get the extremum point.

\frac {dA}{dx}=0

\Rightarrow \frac{135}{2}-9x=0

\Rightarrow x=\frac{15}{2}

Check this point by double differentiation

\frac {d^2A}{dx^2}=-9

As,  \frac {d^2A}{dx^2}, so, point x=\frac{15}{2} is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2

\Rightarrow A=253.125 m^2

Hence, the range of area function is (0, 253.125 m^2].

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Reika [66]
A
x=y^2-9
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square root both sides
+-sqrt(x+9)
7 0
2 years ago
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