H = 151t - 16t²
The height of the ball when it return to the ground will be 0
0 = 151t - 16t²
The zero product property is that when two numbers are being multiplied and the product is 0, one of them must be equal to 0. Therefore, we can factorize this equation:
16t² - 151t = 0
t(16t - 151t) = 0
By the zero product property:
t = 0 or 16t - 151 = 0
So t = 0 or t = 9.44 seconds
The first solution is before he releases the ball and the second is when the ball comes back to the ground. Thus, the ball's air time is 9.44 seconds.
Answer:
Step-by-step explanation:
Th average rate of change is the slope of the secant line that goes through those 2 values of x. Of course, each value of x also has a value of y. The coordinates for these combinations of x's and y's are:
(-1, 5) and (4, 0). We can use the slope formula to find the average rate of change of this function without having to know what the function's equation is:
So the average rate of change, aka slope, between those 2 points is -1
120 - 96 = 24
Now we have to find what percent of 120 24 is.
x × 120 = 24
x = 0.2
0.2 means 20%.
The discount is 20% off.
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