Please help asapp it's for a test

1.) You are the crew chief of the Algebra 2 formula racing team. Your current task is to

s344n2d4d5 [400]

Answer:

a). Mileage for carA= $\frac{2}{x}$ , and mileage for carB= $\frac{ 3x+2}{x(x+1)}$

b).total mileage for both is similar to average of them= $\frac{(mileageA + mileageB)}{2}$

= $\frac{5x+4}{2x(x+1)}[tex]mil/gal$

Step-by-step explanation:

It is given that the distance traveled by car $A=2x+2=2(x+1)$

And distance traveled by car $B= 3x+2$

We know the mileage is mile/gallon,

a).So mileage of car $A= \frac{distance traveled by car A}{gallos of fuel used}$

$=\frac{2x+2}{x^2 +x}\\ =\frac{2(x+1)}{x(x+1)} \\=\frac{2}{x}mil/gal$

Similarly , the mileage for car $B= \frac{distance traveled by car A}{gallons of fuel used}$

$=\frac{3x+2}{x^2+x} \\=\frac{3x+2}{x(x+1)}$ $mil/gal$

b).total mileage for both is similar to average of them= $\frac{(mileageA + mileageB)}{2}$

$=\frac{2x+2}{x(x+1)}+\frac{3x+2}{x(x+1)}\\ =\frac{2x+2+3x+2}{x(x+1)}\\=\frac{5x+4}{x(x+1)}mil/gal$

Now divide by 2 for total(average) mileage.

$\frac{\frac{5x+4}{x(x+1)} }{2}\\ =\frac{5x+4}{2x(x+1)} mil/gal$ .

Thus those are the answers.

4 0

3 years ago

Liam and Harper are racing on a track. Liam runs 4 miles per hour and gets a 0.25 miles head start. Harper runs 0.5 mile per hou

igomit [66]

S=d/t
for liam
4=.25/t
t=.25/4
t=0.0625hours
for harper
t=0.25/4.5=0.055hours
msg me if it helps

4 0

4 years ago

Please answer the following questions with the proper significant figures:

mamaluj [8]

Answer:

idont know what's the answer but goodluck bro loveyou

5 0

3 years ago

A golfer takes two putts to get the ball into the hole. The first putt rolls the ball 10.3 feet in the northwest direction and t

creativ13 [48]

Let's put this on the usual Cartesian grid just so we can talk about it without drawing a picture. We'll use map conventions, right is east, up is north.

The ball starts at (0,0). 10.3 feet northwest means we have an isosceles right triangle whose diagonal is 10.3 feet. It's isosceles because northwest means equal parts north and west.

The sides of these triangles are in ratio $1:1:\sqrt{2}$ so the coordinates after the first putt are

$(- 10.3 / \sqrt{2}, 10.3 / \sqrt{2})$

The negative sign indicates west, which doesn't really matter for this problem. The distance from the origin to this point is 10.3 as required.

Now a second putt of 3.8 feet north puts us at

$(- 10.3 / \sqrt{2}, 10.3 / \sqrt{2} + 3.8)$

The squared distance to the origin is exactly

$d^2 = 10.3^2/2 + (10.3 / \sqrt{2} + 3.8)^2$

A little calculator work tells us

$d \approx 13.2621$

Third choice.

3 0

3 years ago

NO SCAM. PLEASE SHOW WORK. WILL GIVE BRAINLY TO CORRECT ANSWER.

sergeinik [125]

Answer:

$140$