Well 5 1/4 hours is 5 hours and 15 minutes and 2/3 of 5 hours and 15 minutes or 315(5*60+15) is 210
hope it helped
Easy
quadratic means 2nd degree
means highest power of exponent is 2
so like x^2
first one
we have 3x^3, that is 3rd degree,nope
2nd one
we have 8x^4, nope, that is 4th degree
3rd one
we have -x^2, yep
4th one, we have 9x^4, that is 4th degree
answer is 3rd one or p(x)=-5x-x^2
Answer: 16 double rooms and 10 single rooms were rented.
Step-by-step explanation:
Let x represent the number of double rooms that were rented.
Let y represent the number of single rooms that were rented.
The total number of rooms rented in a day is 26. It means that
x + y = 26
A motel rents double rooms at $34 per day and single rooms at $26 per day. If all the rooms that were rented for one day cost a total of $804, it means that
34x + 26y = 804 - - - - - - - - - - -1
Substituting x = 26 - y into equation 1, it becomes
34(26 - y) + 26y = 804
884 - 34y + 26y = 804
- 34y + 26y = 804 - 884
- 8y = - 80
y = - 80/ - 8 = 10
x = 26 - y = 26 - 10
x = 16
Here! :) i hope this helps bunny!
Answer:
Kinetic theory explains why the volume of a container must expand when the temperature of the gas inside increases in order for the pressure to remain constant.
Step-by-step explanation:
Charles' law: for a fixed mass of gas at constant pressure the volume is directly proportional to the temperature.
Analysis of a gas when its temperature increases according to kinetic theory:
The temperature has increased therefore the molecules have more kinetic energy, so they move with a greater velocity.¹
If the container's dimensions do not change the molecules will travel across the container between the walls in less time (because they are moving faster and covering the same distance between the container walls). This will increase the rate of collisions, which would increase the pressure.²
But if the dimensions of the container increased then the molecules would cover a larger distance faster thereby maintaining a constant rate of collisions. This would maintain a constant pressure.