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Maurinko [17]
2 years ago
7

Yen paid $10.50 for 2.5 pounds of pretzels what price did she pay for each pound pretzels?​

Mathematics
2 answers:
Likurg_2 [28]2 years ago
8 0

Answer:4.2

Step-by-step explanation:

arsen [322]2 years ago
4 0
4.2$ for each pound of pretzels
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Plz help
kvv77 [185]

Option C: 5 x(4 x+7)(3 x+2) is the possible expressions for length, width and height of the prism.

Explanation:

The volume of the rectangular prism is 60 x^{3}+145 x^{2}+70 x

To determine the length, width and height of the rectangular prism, let us factor the expression.

Thus, factoring 5x from the expression, we have,

5 x\left(12 x^{2}+29 x+14\right)

Let us break the expression 12 x^{2}+29 x+14 into two groups, we get,

5x[\left(12 x^{2}+8 x\right)+(21 x+14)]

Factoring 4x from the term 12 x^{2}+8 x , we get,

5x[4 x(3 x+2)+(21x+14)]

Similarly, factoring 7x from the term 21 x+14 , we get,

5x[4 x(3 x+2)+7(3x+2)]

Now, let us factor out 3x+2, we get,

5 x(4 x+7)(3 x+2)

Hence, the possible expressions for length, width and height of the prism is 5 x(4 x+7)(3 x+2)

Therefore, Option C is the correct answer.

8 0
3 years ago
During the summer months, science center tickets are 3 for $36.75 and zoo tickets are 4 for $51.00. How much will a group of 12
german
The science group will save $6 dollars
5 0
3 years ago
Suppose that receiving stations​ X, Y, and Z are located on a coordinate plane at the points ​(6​,2​), ​(negative 2​,negative 4​
marin [14]

Answer:

  (2,-1)

Step-by-step explanation:

A graph is useful here. Points X and Y have coordinate differences of ...

  X -Y = (6, 2) -(-2, -4) = (6+2, 2+4) = (8, 6)

Then the distance between X and Y is ...

  d = √(8² +6²) = √100 = 10

The point 5 units from X and from Y is the midpoint of XY:

  E = (X +Y)/2 = ((6, 2) +(-2, -4))/2 = (4, -2)/2 = (2, -1)

The epicenter is (2, -1).

_____

The graph shows circles of radius 5 around X and Y, and a circle of radius 13 around Z. The circles intersect at the point (2, -1), the epicenter.

5 0
2 years ago
The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra
Snezhnost [94]
Let X denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by X_1,\ldots,X_{36}, each independently and identically distributed with distribution X_i\sim\mathcal N(26,7.2).

You want to find

\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)

Recall that if X\sim\mathcal N(\mu,\sigma), then the sampling distribution \overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right) with n being the size of the sample.

Transforming to the standard normal distribution, you have

Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}

so that in this case,

Z=6\dfrac{\overline X-26}{7.2}

and the probability is equivalent to

\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)
=\mathbb P(Z>1.481)\approx0.0693
5 0
3 years ago
Me banks left work at 5:15cpm it took him 1 1/4 hours to drive home at what time did me banks arrive home
katen-ka-za [31]

Answer:

the answer would be 6:30 pm

Step-by-step explanation:

if you left work at 5:15 and it took 1 1/4 min to get home

you would

find 1/4 witch would be 15 min because 60/4= 15  

then add 1:15 to 5:15

1:15 + 5:15 = 6:30 pm

you arrived home at 6:30 pm

4 0
3 years ago
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