If 6 j of work is needed to stretch a spring from 9 cm to 11 cm and another 10 j is needed to stretch it from 11 cm to 13 cm, the natural length (in cm) of the spring will be 7cm
The restoring force is a function only of position of the mass or particle, and it is always directed back toward the equilibrium position of the system. The restoring force is often referred to in simple harmonic motion. The force which is responsible to restore original size and shape is called restoring force.
In physics, Hooke's law is an empirical law which states that the force (F) needed to extend or compress a spring by some distance (x) scales linearly with respect to that distance—that is, Fs = kx, where k is a constant factor characteristic of the spring (i.e., its stiffness), and x is small compared to the total possible deformation of the spring.
6 = 
6 = 1/2 k
lm (9 - l) to (11 - l)
6 = 1/2 k [
-
]
12/k = 40 - 4l equation 1
10 = 
10 = 1/2 k
lm (13 - l) to (11 - l)
20 k = 48 -4l equation2
solving equation 1 and 2 , we get
12/20 = 40 - 4 l / 48 -4 l
l = 7 cm
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Because they have added another solution, it means that the mixture was not yet saturated, so the correct answer is unsaturated, D
force × distance = work done
4200N × 1609m = 6,757,800Nm
Answer:
Newton
is the answer of si unit of force
The power expended is 500 W
Explanation:
First of all, we start by calculating the work done by the man in order to ascend: this is equal to the gravitational potential energy gained by the man, which is

where
m = 50 kg is the mass of the man
is the acceleration of gravity
is the change in height
Substituting,

Now we can calculate the power expended, which is given by

where
W = 2500 J is the work done
t = 5 s is the time elapsed
Substituting, we find

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