Why is being geosynchronous important for telecommunications satellites
1 answer:
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Answer:
1020.4kg/m³
35m³
Explanation:
Given parameters:
Depth = 0.5m
Pressure exerted = 5000N/m²
Unknown = density of the liquid = ?
Solution:
To find the density of this unknown liquid, we use the expression below:
Pressure of liquid = density x height x acceleration due to gravity
5000 = density x 0.5 x 9.8
Density = 1020.4kg/m³
B.
Density of water = 1000kg/m³
Mass of water = 35000kg
Unknown:
Volume of water = ?
Solution:
The volume of water can be derived from the expression below:
Volume =
Volume = = 35m³
