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3 years ago

If the two spheres are then connected by a conducting wire what will be the final charges on the spheres?

1 answer:

3 0

Sounds like this is part of another question.
If the charges on both are of the same sign but different charge magnitude then each will become
(a + b)/2

If the charges are different in sign and of different magnitudes then
| a - b| / 2 is the charge on both.

If the charges are = but of different sign, then each sphere will have a magnitude of 0.

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An Earth satellite is orbiting at a distance from the Earth's surface equal to one Earth radius (4 000 miles). At this location,

Taya2010 [7]

Answer:0.25 times

Explanation:

Given

Distance of satellite from earth surface=Radius of earth

Force on the satellite is F=mg'

where g'=acceleration due to gravity at that point

Distance from center of Earth=R+R=2R

Gravitational Force is given by

$F=\frac{GM_1M_2}{r^2}$

Force $F=mg'=\frac{GMm}{4R^2}-----1$

Force on earth surface $F=mg=\frac{GMm}{R^2}------2$

Divide 1 and 2 we get

$\frac{g'}{g}=\frac{R^2}{4R^2}$

$g'=\frac{g}{4}$

7 0

3 years ago

This type of liquid can be used as an electric tester Is that a good conducted of electricity?

Helga [31]

Answer:

Yes

Explanation:

Testing electricity is a good conductor of electricity.

7 0

2 years ago

In 10 seconds a car accelerates 4m/s^2 to 50

DanielleElmas [232]

Answer:

10m/s

Explanation:

using the formula a=v-u

4 0

2 years ago

In an oil drop experiment, a drop with a weight of 1.9 x 10-14 N was suspended when the potential difference between 2 plates th

AlekseyPX

Answer:

Study More You will get it :L

5 0

2 years ago

If the 50 kg boy were in a spacecraft 5.0r from the center of the earth, what would his weight be?

Lady_Fox [76]

·The acceleration of gravity is proportional to

   1 / (the square of the distance from the center) .

When we're on the surface, we're 1 radius from the center of the Earth,
and the acceleration of gravity is 9.8 m/s² .

The boy's weight = (mass) · (gravity) = (50kg) · (9.8 m/s²)

   = 490 newtons .

At the distance of 5 radii from the center (4 radii altitude from the surface),
the acceleration of gravity is

   (9.8 m/s²) · (1/5)² = 0.39 m/s² .

The boy's weight is (mass) · (gravity) = (50kg) · (0.39 m/s²)

= 19.6 newtons .

Just as we expected, his weight at that distance is

   (19.6 / 490) = 0.04 = 1/25 = 1/5² of his weight on the surface.

7 0

2 years ago