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joja [24]
3 years ago
6

When testing for current in a cable with eleven color-coded wires, the author used

Mathematics
1 answer:
ddd [48]3 years ago
6 0
Answer:

The number of test required is: 55

Explanation:

Using combination formula:

n!/x!(n-x)!

= 11!/2!(9)!

= 55
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Solve the inequality and enter your solution as an inequality comparing the
avanturin [10]

Answer: x > 20

Step-by-step explanation:

x + 10 > 30

    -10     -10

x > 20

3 0
3 years ago
Read 2 more answers
What is the expansion of (3+x)^4
Vlad1618 [11]

Answer:

\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81

Step-by-step explanation:

Considering the expression

\left(3+x\right)^4

Lets determine the expansion of the expression

\left(3+x\right)^4

\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i

a=3,\:\:b=x

=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i

Expanding summation

\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}

i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0

i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1

i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2

i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3

i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

as

\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81

\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x

\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2

\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3

\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4

so equation becomes

=81+108x+54x^2+12x^3+x^4

=x^4+12x^3+54x^2+108x+81

Therefore,

  • \left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81
6 0
3 years ago
Evaluate the given expression if a​ = 2 and ​b​ = -4 <br> a2-b3
IceJOKER [234]

Answer:

31

Step-by-step explanation:

{a}^{2}  -  {b}^{3}  \\  \\  =  {(2)}^{2}  -  {( - 3)}^{3}  \\  \\  = 4 - ( - 27) \\  \\  = 4 + 27 \\  \\  = 31

5 0
3 years ago
A football team played A games last year. They lost B of those games. What was their winning percentage? 
Alexeev081 [22]
Winning%=100[wins/(total games)]

w%=100(A-B)/A

So the way that your choice expressed that is:

(A-B)/A x 100
7 0
3 years ago
Which posulate proves the two triangles are congruent?
san4es73 [151]

Answer:

D ASA

Step-by-step explanation:

ASA

5 0
2 years ago
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