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bija089 [108]
3 years ago
13

You are at a restaurant and the check comes to a total of $23. If you want to leave a 20% tip, how much total money should you p

ay, to the nearest cent?
Mathematics
1 answer:
Oxana [17]3 years ago
8 0

Answer:

$27.60

Step-by-step explanation:

23×1.2=27.60 is the answer

You might be interested in
Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and
zloy xaker [14]

Answer:

(0,0)   (4000,0) and (500,79)

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW

\frac{dW}{dt} = -0.02W + 0.00004RW

To solve this, we first equate \frac{dR}{dt} and \frac{dW}{dt} to 0.

So, we have:

0.09R(1 - 0.00025R) - 0.001RW = 0

-0.02W + 0.00004RW = 0

Factor out R in 0.09R(1 - 0.00025R) - 0.001RW = 0

R(0.09(1 - 0.00025R) - 0.001W) = 0

Split

R = 0   or 0.09(1 - 0.00025R) - 0.001W = 0

R = 0   or  0.09 - 2.25 * 10^{-5}R - 0.001W = 0

Factor out W in -0.02W + 0.00004RW = 0

W(-0.02 + 0.00004R) = 0

Split

W = 0 or -0.02 + 0.00004R = 0

Solve for R

-0.02 + 0.00004R = 0

0.00004R = 0.02

Make R the subject

R = \frac{0.02}{0.00004}

R = 500

When R = 500, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0

0.09 -0.01125 - 0.001W = 0

0.07875 - 0.001W = 0

Collect like terms

- 0.001W = -0.07875

Solve for W

W = \frac{-0.07875}{ - 0.001}

W = 78.75

W \approx 79

(R,W) \to (500,79)

When W = 0, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0

0.09 - 2.25 * 10^{-5}R = 0

Collect like terms

- 2.25 * 10^{-5}R = -0.09

Solve for R

R = \frac{-0.09}{- 2.25 * 10^{-5}}

R = 4000

So, we have:

(R,W) \to (4000,0)

When R =0, we have:

-0.02W + 0.00004RW = 0

-0.02W + 0.00004W*0 = 0

-0.02W + 0 = 0

-0.02W = 0

W=0

So, we have:

(R,W) \to (0,0)

Hence, the points of equilibrium are:

(0,0)   (4000,0) and (500,79)

4 0
3 years ago
What number increased by 62%, results in the value of 59.94
lakkis [162]

Answer:

The number is : x = 37

Step-by-step explanation:

In order to solve this question, we may set up a proportion.

If the original number is 100%, 59.94 would be 162% of the original, as it was increased by 62%.

so

59.94 → 162%

x → 100%

solving the proportion gives you  

59.94 × 100 = 162 × x

x = (59.94 × 100)/162

x =  5994/162

x= 37

Thus, the number is : x = 37

4 0
3 years ago
Find the interest rate r given I=$ 56,P=450 and t = 6 years , round your answer to the nearest
m_a_m_a [10]

Answer:

0.163

Step-by-step explanation:

P = I (1 + r)ᵗ

450 = 56 (1 + r)⁶

8.036 = (1 + r)⁶

log₆ 8.036 = 1 + r

log 8.036 / log 6 = 1 + r

1.163 = 1 + r

r = 0.163

5 0
3 years ago
Find the sum of the counting numbers from 1 to 25 inclusive. In other words, if S = 1 + 2 + 3 + ... + 24 + 25, find the value of
Anastaziya [24]

Answer:

325

Step-by-step explanation:

You must have heard about Arithmetic Progressions (AP)

Arithmetic progressions are a series of numbers such that every successive number is the sum of a constant number and the previous number.

Our very own counting numbers form AP

For example :-

2 = 1 + <u>1</u>

3 = 2 + <u>1</u>

4 = 3 + <u>1</u>

The number in bold (1) is that constant number which is added to a number to form its successive number.

To find the sum of series forming AP, we use the formula :-

sum =  \frac{n}{2} \{ a  + a  _{n}  \}

here,

  • n is the number of terms
  • a is the first number of the series
  • an is the last number of the series

So we'll use all this information to find the sum of continuous numbers from 1 to 25 where 1 is the first term(a) and 25 is the last(an).

and n is 25

S  =   \frac{25}{2}\{ 1  +25\}

=  \frac{25 \times 26}{2}

= 25  \times 13

= 325

So, the value of S comes out to be 325.

8 0
3 years ago
Read 2 more answers
A triangle on a coordinate plane is translated according to the rule Ias(x, y). Which is another way to write this rule?
Mrrafil [7]
The answer is the third
3 0
3 years ago
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