Answer:
The answer is either 9/200 (nine two-hundreths) or 22
We know that
∠ TSR = 84°
if SQ bisects ∠ <span>TSR
then
</span>∠ RSQ = ∠ TSR/2
<span>so
</span>∠ RSQ = (1/2)*84°----- 42°
∠ RSQ = 3x-9
3x-9=42-------> 3x=42+9------> 3x=51-----> x=51/3-----> x=17°
<span>
the answer is
</span>x=17°<span>
</span>
Answer:
<u>x = 60°</u>
Step-by-step explanation:
The rest of the question is the attached figure.
And it is required to find the angle x.
As shown, a rhombus inside a regular hexagon.
The regular hexagon have 6 congruent angles, and the sum of the interior angles is 720°
So, the measure of one angle of the regular hexagon = 720/6 = 120°
The rhombus have 2 obtuse angles and 2 acute angles.
one of the obtuse angles of the rhombus is the same angle of the regular hexagon.
So, the measure of each acute angle of the rhombus = 180 - 120 = 60°
So, the measure of each acute angle of the rhombus + the measure of angle x = the measure of one angle of the regular hexagon.
So,
60 + x = 120
x = 120 - 60 = 60°
<u>So, the measure of the angle x = 60°</u>
Answer:
A
Step-by-step explanation:
5:9 is the original ratio.
we know that anything times 5 would have the ones place of either 5 or 0 so we can eliminate c and d. Then we test out the other two choices.
25/5=5
45/9=5
A is correct.
15/5=3
45/9=5
Option B is incorrect.
so, the ratio is 25:45
The answer is A!
Answer:
5.85 m
Step-by-step explanation:
The width of the sand road can be calculated knowing its area and the dimensions of the rectangular garden as follows:

<u>Where:</u>
Ag: is the area of the rectangular garden
a: is the length of the rectangular garden = 50 cm = 0.5 m
b: is the width of the rectangular garden = 34 m
<u>Where</u>:
As: is the area of the sand road
The relation between the area of the sand road and the area of the rectangular garden is the following:



By solving the above equation for x we have two solutions:
x₁ = -23.10 m
x₂ = 5.85 m
Taking the positive value, we have that the width of the sand road is 5.85 m.
I hope it helps you!