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Monica [59]
3 years ago
5

What is the value of x to the nearest tenth?

Mathematics
1 answer:
Stolb23 [73]3 years ago
7 0
X = 6 / tan(67)

x = 2.546

rounded to nearest tenth x = 2.5
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How do I work out 2x + 37 = 8x + 7
Setler [38]
You have to make sure that whatever you do to one side, you also do to the other.

2x + 37 = 8x + 7
2x + 37 - 2x = 8x + 7 - 2x
37 = 6x + 7
37 - 7 = 6x + 7 - 7
30 = 6x
30 / 6 = 6x / 6
5 = x
x = 5

Hope this helps! :)
7 0
3 years ago
Read 2 more answers
The volume of a 9 inch cube is?
Sedbober [7]
Answer:

A. 729 cu in

Explanation:

Step 1: 9x9 = 81
Step2: 81x9 = 729
8 0
2 years ago
Please help asap!!! URGENT!!!
Elis [28]

Answer:

b = 8√3 mm, a = 16 mm, x = 5 ft, y = 5√2 ft.

Step-by-step explanation:

With 30° 60° 90° triangles, one side will be a number, the other leg will be that number multiplied by √3, and the hypotenuse will be 2 times that original number.

So in this case:

The original leg's length is 8 mm. Side b will be that 8 times √3.

So, b = 8√3 mm.

Side a will be 8 times 2.

So, a = 16 mm.

With 45° 45° 90° triangles, the two legs will be the same length, and the hypotenuse will be that number times √2.

So in this case:

The original leg's length is 5 ft. Side x will be that same length.

So, x = 5 ft.

Side y will be 5 times √2.

So, y = 5√2 ft.

3 0
3 years ago
Robert works at a car dealership. Each month, he receives a base salary of $1,854.00, plus a commission of $478.00 for each vehi
Maksim231197 [3]

Answer:

y = 478x + 1,854

Step-by-step explanation:

8 0
3 years ago
write the slope intercept form of the equation of the line with a slope of -2/5 that passes through 15, -9/2​
Sever21 [200]

Answer:

The equation of line in slop-intercept form  is y = \dfrac{-2x}{5} + \dfrac{3}{2}

Step-by-step explanation:

Given as :

The slope of the a line = m = \dfrac{-2}{5}

The line is passes through points x_1 , y_1 = 15 , \dfrac{- 9}{2}

<u>According to question</u>

Equation of line in slope - intercept form

y - y_1 = m × ( x - x_1 )

Or, y - (\dfrac{- 9}{2} ) =  \dfrac{-2}{5} × ( x - 15 )

Or, y  - (\dfrac{- 9}{2} ) =  \dfrac{-2}{5} ×  x  - ( \dfrac{-2}{5} ) × 15

Or, y  - (\dfrac{- 9}{2} ) =  \dfrac{-2}{5} ×  x  + 6

Or, y =   \dfrac{-2}{5} ×  x  + 6 - \dfrac{9}{2}

Or, y =   \dfrac{-2}{5} ×  x  + \dfrac{12-9}{2}

Or, y = \dfrac{-2}{5} ×  x + \dfrac{3}{2}

So, The equation of line in slop-intercept form  y = \dfrac{-2}{5} ×  x + \dfrac{3}{2}

Hence, The equation of line in slop-intercept form  is y = \dfrac{-2x}{5} + \dfrac{3}{2}  Answer

6 0
3 years ago
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