Question

Use row reduction to solve the system of equations.

Answer 1

Answer:

$x=-1223,y=-629,z=-31$

Step-by-step explanation:

The given systems of equations is

$x-2y+z=4$

$3x-5y-17z=3$

$2x-6y+43z=-5$

The augmented matrix is

$\left[\begin{array}{cccc}1&-2&1&|\:\:\:\:4\\3&-5&-17&|\:\:\:\:3\\2&-6&43&|-5\end{array}\right]$.

We perform the following row operations to reduce the matrix to reduced row echelon form using row 1 as our pivot row.

$R_2-3R_1\rightarrow R_2$

$R_3-2R_1\rightarrow R_3$

$\left[\begin{array}{cccc}1&-2&1&|\:\:\:\:\:\:\:\:\:\:4\\0&1&-20&|\:\:\:\:-9\\0&-2&41&|-13\end{array}\right]$

Next, we perform the following row operations using row 2 as our pivot row to obtain,

$R_1+2R_2\rightarrow R_1$

$R_3+2R_2\rightarrow R_3$

$\left[\begin{array}{cccc}1&0&-39&|-14\\0&1&-20&|\:\:-9\\0&0&1&|-31\end{array}\right]$

Next, we perform the following row operations using row 3 as our pivot row to get,

$R_1+39R_3\rightarrow R_1$

$R_2+20R_3\rightarrow R_2$

$\left[\begin{array}{cccc}1&0&0&|\:-1223\\0&1&0&|\:\:\:\:-629\\0&0&1&|\:\:\:\:\:\:-31\end{array}\right]$

The matrix is now in the reduced row echelon form,

Therefore the solution is,

$x=-1223,y=-629,z=-31$