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klio [65]
2 years ago
14

The ratio of boys and girls in a 4:3.If there are 20 boys, find the number of girls.​

Mathematics
2 answers:
rosijanka [135]2 years ago
8 0

Answer:

15

Step-by-step explanation:

Add:

boys : girls

     4 : 3 = 7

    20: ? = ?

Divide:

20 / 4 = 5

5 × 3 = 15

20: 15

So, there are 15 girls.

Elina [12.6K]2 years ago
6 0

Answer:

There are 15 girls.

Step-by-step explanation:

The ratio is 4:3, meaning there are 7 parts.

4 parts= 20 (Boys)

This means 1 part is 20 divided by 4.

1 part= 5

3 parts= Amount of girls.

3 x 5 = 15.

There are 15 girls.

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pshichka [43]

Answer:1 2/5

Step-by-step explanation:

8 1/5 = 41/5

6 4/5 = 34/5

41/5 - 34/5 = 7/5 which is the same as 1 2/5

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3 years ago
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I'm not sure about my answer I think it's b or c ​
Sonja [21]

Answer: its actually a

Step-by-step explanation:

A = -5 ( -9 / 3 = -3; -3 -2 =-5)

B= - 2

C = -2

D = 0

4 0
3 years ago
Fill in the blanks to complete the area model to solve 6.60 divided by 15 is the same as _ x ? = _ 6.60 = _ hundredths
storchak [24]

Answer:

15 x = 6.60

x = 44\ hundredths

Step-by-step explanation:

Given

\frac{6.60}{15}

Required

Complete the model

[ ] x = 6.60

x = _ hundredths

\frac{6.60}{15}

Equate to x

x = \frac{6.60}{15}

Multiply both sides by 15

15 * x = \frac{6.60}{15} * 15

15 * x = 6.60

15 x = 6.60

So, we have:

[ ] x = 6.60 =====> 15 x = 6.60

Recall that:

x = \frac{6.60}{15}

x = 0.44

This implies that:

x = 44\ hundredths

Hence:

x = _ hundredths =====> x = 44\ hundredths

3 0
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Anarel [89]

Answer:

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6 0
3 years ago
What is the measure of EAB in circle F?<br> 72°<br> 92°<br> 148°<br> 200°
Arada [10]

We have been given a diagram. We are asked find the measure of arc EAB.

First of all, we will find the measure of arcs ED and CB using our given information.

We know that measure of an inscribed angle is half the measure of intercepted arc.

We can see that angle EBC is inscribed angle of arc EDC, so measure of arc EDC will be twice the measure of angle EBC.

\widehat{EDC}=2\times m\angle EBC

\widehat{EDC}=2\times 80^{\circ}

\widehat{EDC}=160^{\circ}

Similarly, we will find the measure of arc DCB.

\widehat{DCB}=2\times m\angle DEB

\widehat{DCB}=2\times 70^{\circ}

\widehat{DCB}=140^{\circ}

\widehat{ED}=\widehat{EDC}-\wdiehat{DC}

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\widehat{EAB}=360^{\circ}-212^{\circ}

\widehat{EAB}=148^{\circ}

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8 0
3 years ago
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