Answer:
p is approximately equal to 1.125, -1.925
Step-by-step explanation:
We can solve this first by expanding, giving us a quadratic equation in the usual ax² + bx + c format, then solving that for p:
(4p - 4)(13p + 27) = 0
52p² + 108p - 52p - 108 = 0
52p² + 52p - 108 = 0
13p² + 13p - 27 = 0
13p² + 13p = 27
p² + p = 27 / 13
p² + p + 1/4 = 27/13 + 1/4
(p + 1/2)² = 108 / 52 + 13 / 52
(p + 1/2)² = 121 / 52
p + 1/2 = ± √(121 / 52)
p = -1/2 ± 11√(1/13) / 2
At that point we can simply plug those numbers into a calculator and solve it:
p ≈ 1.125, -1.925
Answer:
Step-by-step explanation:
<u>Using the distance formula</u>:
Answer:
Domain: (-5,-4,-3,-2,-1,0,1,2,3,4,5)
Range: (0,1,2,3,4, -1, -2)
Step-by-step explanation:
Domain means all of the x-axis values on the graph, so for example in (-2,0), -2 would be part of the domain and 0 part of the range. Therefor, what you would do would be take all of the plots and put all x values as the domain and all y values as the range. Hope this helped!
Sorry if it is wrong but i think it is D) 2 multiplied by fraction 1 over 3 m2
Answer:
Initial value is 
.
Step-by-step explanation:
Let us assume that the exponential function is 
...... (1)
Now, the point 
will satisfy the above equation.
Now, this point on the graph of the exponential function will be sufficient to find the initial value of the function (1) i.e. a.
Now, putting the value x = 0 and 
in the equation (1) we get,
⇒ 
⇒ 
(Answer)
