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vaieri [72.5K]
3 years ago
9

What is (2x^2+6x-3) added to (2x^3-3x+2)?

Mathematics
2 answers:
Bas_tet [7]3 years ago
8 0
2x² + 6x - 3 + 2x³ - 3x + 2

Combine like terms

2x³ + 2x² + 6x - 3x - 3 + 2

Final answer:
2x³ + 2x² + 3x - 1
aleksklad [387]3 years ago
6 0
2x^3 + 2x^2 + 3x - 1   would be result 


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What is the simplified form of -24m^5 n^4/ 8m^-7 n^-2
solong [7]

Answer:

  -3·m^12·n^6

Step-by-step explanation:

We assume you intend ...

  (-24·m^5·n^4)/(8·m^-7·n^-2)

  = (-24/8)·m^(5-(-7))·n^(4-(-2))

  = -3·m^12·n^6

_____

If you really intend what you have written, then it simplifies to ...

  (-24·m^5·n^4/8)·m^-7·n^-2 . . . . . note that all factors involving m and n are in the numerator

  = (-24/8)·m^(5-7)·n^(4-2) = -3n^2/m^2

8 0
3 years ago
Please click the picture and help me :D
harkovskaia [24]
Well first of all, let's define what an integer is...

Integers are numbers such as -2, -1, 0, 1, 2 etc etc.

------

If f(5)=12,

f(6)=0.3*f(6-1)

= 0.3*f(5)

= 0.3*12

= 3/10 * 12

= 36/10

= 3.6

We now know that f(6)=3.6

Now:

f(7)=0.3*f(7-1)

= 0.3*f(6)

= 0.3*3.6

= (3/10) * (36/10)

= 108/100

= 1.08

Answer:

f(7)=1.08
4 0
4 years ago
Which group shows 0.25 of the faces smiling?
Ivahew [28]

Answer:

My dude the groul that shows that tiny bit of smiling must be the beatles or backstreet boys

6 0
3 years ago
Solve the inequality -6c< -12
sweet [91]

Answer: c<2

Step-by-step explanation:

-6c<-12

c<-12/-6

c<2

7 0
3 years ago
Lines 3x-2y+7=0 and 6x+ay-18=0 is perpendicular. What is the value of a?
BlackZzzverrR [31]

Answer:

\boxed{\sf a = 9 }

Step-by-step explanation:

Two lines are given to us which are perpendicular to each other and we need to find out the value of a . The given equations are ,

\sf\longrightarrow 3x - 2y +7=0

\sf\longrightarrow 6x +ay -18 = 0

Step 1 : <u>Conver</u><u>t</u><u> </u><u>the </u><u>equations</u><u> in</u><u> </u><u>slope</u><u> intercept</u><u> form</u><u> </u><u>of</u><u> the</u><u> line</u><u> </u><u>.</u>

\sf\longrightarrow y = \dfrac{3x}{2} +\dfrac{ 7 }{2}

and ,

\sf\longrightarrow y = -\dfrac{6x }{a}+\dfrac{18}{a}

Step 2: <u>Find </u><u>the</u><u> </u><u>slope</u><u> of</u><u> the</u><u> </u><u>lines </u><u>:</u><u>-</u>

Now we know that the product of slope of two perpendicular lines is -1. Therefore , from Slope Intercept Form of the line we can say that the slope of first line is ,

\sf\longrightarrow Slope_1 = \dfrac{3}{2}

And the slope of the second line is ,

\sf\longrightarrow Slope_2 =\dfrac{-6}{a}

Step 3: <u>Multiply</u><u> </u><u>the </u><u>slopes </u><u>:</u><u>-</u><u> </u>

\sf\longrightarrow \dfrac{3}{2}\times \dfrac{-6}{a}= -1

Multiply ,

\sf\longrightarrow \dfrac{-9}{a}= -1

Multiply both sides by a ,

\sf\longrightarrow (-1)a = -9

Divide both sides by -1 ,

\sf\longrightarrow \boxed{\blue{\sf a = 9 }}

<u>Hence </u><u>the</u><u> </u><u>value</u><u> of</u><u> a</u><u> </u><u>is </u><u>9</u><u> </u><u>.</u>

8 0
3 years ago
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