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2 years ago

What is (2x^2+6x-3) added to (2x^3-3x+2)?

Mathematics

2 answers:

Bas_tet [7]2 years ago

8 0

2x² + 6x - 3 + 2x³ - 3x + 2

Combine like terms

2x³ + 2x² + 6x - 3x - 3 + 2

Final answer:
2x³ + 2x² + 3x - 1

aleksklad [387]2 years ago

6 0

2x^3 + 2x^2 + 3x - 1 would be result

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The explicit formula for the geometric sequence 10,30,90,180

alukav5142 [94]

Answer:

$a_{n}$ = 10 $(3)^{n-1}$

Step-by-step explanation:

The n th term of a geometric sequence is

$a_{n}$ = a $(r)^{n-1}$

where a is the first term and r the common ratio

Here a = 10 and r = 30 ÷ 10 = 3, thus

$a_{n}$ = 10 $(3)^{n-1}$

7 0

2 years ago

Read 2 more answers

Factor the expression and simplify as much as possible. 24x(x2 1)4(x3 1)5 42x2(x2 1)5(x3 1)4

zmey [24]

Answer: 120[4(x^6 + x^3 + x^4 + x) +7(x^7 + x^4 + x^5 + x^2)]

Step-by-step explanation:

=24x(x^2 + 1)4(x^3 + 1)5 + 42x^2(x^2 + 1)5(x^3 + 1)4

Remove the brackets first

=[(24x^3 +24x)(4x^3 + 4)]5 + [(42x^4 +42x^2)(5x^3 + 5)4]

=[(96x^6 + 96x^3 +96x^4 + 96x)5] + [(210x^7 + 210x^4 + 210x^5 + 210x^2)4]

=(480x^6 + 480x^3 + 480x^4 + 480x) + (840x^7 + 840x^4 + 840x^5 + 840x^2)

Then the common:

=[480(x^6 + x^3 + x^4 + x) + 840(x^7 + x^4 + x^5 + x^2)]

=120[4(x^6 + x^3 + x^4 + x) +7(x^7 + x^4 + x^5 + x^2)]

6 0

2 years ago

The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require

grigory [225]

Answer:

142.2 meters.

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.

Let us find total surface area of box using surface area formula of cuboid.

$\text{Total surface area of cuboid}=2(lb+bh+hl)$ , where,

$l$ = Length of cuboid,

$b$ = Breadth of cuboid,

$w$ = Width of cuboid.

$\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)$

$\text{Total surface area of box}=2(2520+432+840)$

$\text{Total surface area of box}=2(3792)$

$\text{Total surface area of box}=7584$

Therefore, the total surface area of box will be 7584 square cm.

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

$\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}$

$80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2$

$\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=14220\text{ cm}$

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}$

$\text{ Length of canvass}=142.20\text{ m}$

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0

3 years ago

What is the probability that you get two even numbers if you roll two dice?

RoseWind [281]

Answer:

Probability of both even is 12×12=14. Given they are both even there are 3 possible even numbers: 2,4,6.

Step-by-step explanation:

3 0

2 years ago

Answer this for branlist if get right

dusya [7]

Answer:

The median and IQR

Step-by-step explanation:

4 0

2 years ago